A 100.0 mL solution containing 0.918 g of maleic acid (MW = 116.072 g/mol) is titrated with Ö.298 M RÖH. Calculate the pH of the solution after the addition of 53.0 ml. of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27. pH = At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H,M, HM¯ , and M²-, which represent the fully protonated, intermediate, and fully deprotonated forms, respectively. (M²-] = | [HM) = (H,M] =

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A 100.0 mL. solution containing 0.918 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.298 M KOH. Calculate the
pH of the solution after the addition of 53.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27.
pH =
At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic
acid are abbreviated as H,M, HM", and M²-, which represent the fully protonated, intermediate, and fully deprotonated
forms, respectively.
M.
[M²-] =
[HM"] =
(H,M| =
Transcribed Image Text:A 100.0 mL. solution containing 0.918 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.298 M KOH. Calculate the pH of the solution after the addition of 53.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27. pH = At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H,M, HM", and M²-, which represent the fully protonated, intermediate, and fully deprotonated forms, respectively. M. [M²-] = [HM"] = (H,M| =
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