A 10.00-g sample containing an analyte was transferred to a 250-mL volumetric flask and į diluted to volume. When a 10.00-mL aliquot of the resulting solution was diluted to 25.00 mL it was 0,235 found to give a signal of o.235 (arbitrary units). A second 10.0o-mL aliquot was spiked with 10.00 mL of a 1.00- ppm standard solution of the analyte and diluted to 25.00 mL. The signal for the spiked sample was found to be o.502. Calculate the weight percent of analyte in the original sample.
A 10.00-g sample containing an analyte was transferred to a 250-mL volumetric flask and į diluted to volume. When a 10.00-mL aliquot of the resulting solution was diluted to 25.00 mL it was 0,235 found to give a signal of o.235 (arbitrary units). A second 10.0o-mL aliquot was spiked with 10.00 mL of a 1.00- ppm standard solution of the analyte and diluted to 25.00 mL. The signal for the spiked sample was found to be o.502. Calculate the weight percent of analyte in the original sample.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Sample Problems
> A 10.00-g sample containing an analyte was
transferred to a 250-mL volumetric flask and
diluted to volume. When a 10.00-mL aliquot of the
10 g20m
330,235
resulting solution was diluted to 25.00 mL it was
found to give a signal of o.235 (arbitrary units). A
lomL
25 mL
second 10.00-mL aliquot was spiked with 10.00 mL
of a 1.00- ppm standard solution of the analyte and
diluted to 25.00 mL. The signal for the spiked
* yss sample was found to be o.502. Calculate the weight
percent of analyte in the original sample.
- 0.5 2
25 ML
Ans: 5.50 x 10-2%w
earch
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