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A 1.26 M solution of (R)-2-butanol is mixed with an equal volume of a 0.630 M solution of racemic 2-butanol, and the resulting solution is analyzed in a sample container that is 1 dm long. What observed rotation is expected? The specific rotation of (R)-2-butanol is –13.9 degrees mL g¬ dm-1. deg

A 1.26 M solution of (R)-2-butanol is mixed with an equal volume of a 0.630 M solution of racemic 2-butanol, and the resulting solution is analyzed in a sample container that is 1 dm long. What observed rotation is expected? The specific rotation of (R)-2-butanol is –13.9 degrees mL g¬ dm-1. deg

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Equation is:

optical rotation = [specific rotation constant] * concentration * path length

I think I may be addign the molarities together incorrectly, but I'm not sure and I am having trouble solving for the optical rotation.

**Organic Chemistry** *Loudon | Parise Seventh Edition* *Presented by Macmillan Learning* A 1.26 M solution of (R)-2-butanol is mixed with an equal volume of a 0.630 M solution of racemic 2-butanol, and the resulting solution is analyzed in a sample container that is 1 dm long. What observed rotation is expected? The specific rotation of (R)-2-butanol is -13.9 degrees mL g⁻¹ dm⁻¹. α = ____ deg **Explanation:** This is an exercise in calculating the observed rotation of a mixture of enantiomers using the specific rotation formula. ### Variables: - **(R)-2-butanol concentration**: 1.26 M - **Racemic 2-butanol concentration**: 0.630 M - **Observed path length**: 1 dm - **Specific rotation of (R)-2-butanol**: -13.9 degrees mL g⁻¹ dm⁻¹ ### Diagram Explanation: There are no diagrams or graphs present in this content. The task is to compute the observed rotation (α) of the final solution mixing the optically active (R)-2-butanol with a racemic mixture.
Transcribed Image Text:**Organic Chemistry** *Loudon | Parise Seventh Edition* *Presented by Macmillan Learning* A 1.26 M solution of (R)-2-butanol is mixed with an equal volume of a 0.630 M solution of racemic 2-butanol, and the resulting solution is analyzed in a sample container that is 1 dm long. What observed rotation is expected? The specific rotation of (R)-2-butanol is -13.9 degrees mL g⁻¹ dm⁻¹. α = ____ deg **Explanation:** This is an exercise in calculating the observed rotation of a mixture of enantiomers using the specific rotation formula. ### Variables: - **(R)-2-butanol concentration**: 1.26 M - **Racemic 2-butanol concentration**: 0.630 M - **Observed path length**: 1 dm - **Specific rotation of (R)-2-butanol**: -13.9 degrees mL g⁻¹ dm⁻¹ ### Diagram Explanation: There are no diagrams or graphs present in this content. The task is to compute the observed rotation (α) of the final solution mixing the optically active (R)-2-butanol with a racemic mixture.
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