All the atoms in a conjugated system are _. The fewer electrons involved in the conjugated system, the energy gap between HOMO and LUMO will be _. and therefore the wavelength of the photon involved in the absorption process will be _. Being the energy of the HOMO _ than LUMO's, the process of absorption will take place when an electron goes from _. Considering the molecule on the left, there are _ carbon atoms forming a conjugated system. The picture on the right _ a resonance form of the picture on the left.
Basics in Organic Reactions Mechanisms
In organic chemistry, the mechanism of an organic reaction is defined as a complete step-by-step explanation of how a reaction of organic compounds happens. A completely detailed mechanism would relate the first structure of the reactants with the last structure of the products and would represent changes in structure and energy all through the reaction step.
Heterolytic Bond Breaking
Heterolytic bond breaking is also known as heterolysis or heterolytic fission or ionic fission. It is defined as breaking of a covalent bond between two different atoms in which one atom gains both of the shared pair of electrons. The atom that gains both electrons is more electronegative than the other atom in covalent bond. The energy needed for heterolytic fission is called as heterolytic bond dissociation energy.
Polar Aprotic Solvent
Solvents that are chemically polar in nature and are not capable of hydrogen bonding (implying that a hydrogen atom directly linked with an electronegative atom is not found) are referred to as polar aprotic solvents. Some commonly used polar aprotic solvents are acetone, DMF, acetonitrile, DMSO, etc.
Oxygen Nucleophiles
Oxygen being an electron rich species with a lone pair electron, can act as a good nucleophile. Typically, oxygen nucleophiles can be found in these compounds- water, hydroxides and alcohols.
Carbon Nucleophiles
We are aware that carbon belongs to group IV and hence does not possess any lone pair of electrons. Implying that neutral carbon is not a nucleophile then how is carbon going to be nucleophilic? The answer to this is that when a carbon atom is attached to a metal (can be seen in the case of organometallic compounds), the metal atom develops a partial positive charge and carbon develops a partial negative charge, hence making carbon nucleophilic.
All the atoms in a conjugated system are _. The fewer electrons involved in the conjugated system, the energy gap between HOMO and LUMO will be _. and therefore the wavelength of the photon involved in the absorption process will be _. Being the energy of the HOMO _ than LUMO's, the process of absorption will take place when an electron goes from _.
Considering the molecule on the left, there are _ carbon atoms forming a conjugated system. The picture on the right _ a resonance form of the picture on the left.
![The image depicts two chemical structures involving aromatic rings and aliphatic substituents.
**Left Structure:**
- The structure consists of a benzene ring, which is characterized by a six-membered carbon ring with alternating double bonds, indicating aromaticity.
- Attached to the benzene ring is a vinyl group (–CH=CH₂) via a single bond, where the second carbon atom in the vinyl group has a methyl group (–CH₃) bonded to it. This forms an isopropenyl group attached to the benzene ring.
**Right Structure:**
- This structure also contains a benzene ring with alternating double bonds, showing its aromatic nature.
- Attached to the benzene ring is a positively charged vinyl group (the carbon closest to the ring is positively charged, denoted by a plus sign).
- The benzene ring has a negative charge, indicated by a minus sign inside a circle.
These chemical structures illustrate the concept of resonance and charge distribution in organic chemistry, showcasing how substituents can alter electron density and stability in aromatic systems.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F29e9c504-8a48-4dca-a13a-6fa87d4a226b%2Fa5b1b7fa-a5a0-468e-bda9-abf1948af854%2F25pn9jm_processed.png&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
![Chemistry](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Chemistry](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Principles of Instrumental Analysis](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Chemistry](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Chemistry](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Principles of Instrumental Analysis](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Organic Chemistry](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Chemistry: Principles and Reactions](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Elementary Principles of Chemical Processes, Bind…](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)