Answered: A 1.00-m solution of acetic acid,…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A 1.00-m solution of acetic acid, CH3COOH, in benzene has a freezing point of 2.96°C. Use the data in the Table to calculate the value of i and suggest an explanation for the unusual result. (Hint: If i is less than 1.0, each formula unit that dissolves yields less than one solute particle, an outcome suggesting aggregation of solute particles.)

Answer is:

i = 0.50; formation of dimers of composition (CH3COOH)2, need steps shown to understand though

TABLE 16.2 Boiling point elevation constants (K,) and freezing point depression constants (K;) for various solvents
Solvent
Boiling point/°C
K,/K-m̟'
Freezing point/°C
K;/K-m̟'
benzene
80.09
2.64
5.49
5.07
camphor
(207.4)*
5.95
176
37.8
cyclohexane
80.73
2.92
6.59
20.8
ethanoic acid (acetic acid)
117.9
3.22
16.64
3.63
nitrobenzene
210.8
5.2
5.7
6.87
trichloromethane
61.17
3.80
-63.41
4.68
water
100.00
0.513
0.00
1.86

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