When 80 mg of an unknown white powder found at a crime scene is dissolved in 1.42 mL of ethan density = 0.789g/mL, normal freezing point -114.6 °C, Kf = 1.99 °C/m), the freezing point is lower -115.6 °C. Which of the following substances could be responsible for this freezing-point depressi (assume the powder is a nonelectrolyte) Show all the work you used to determine the answer. a) meta-tyramine (C8H₁NO: MM = 137.182 g/mol) b) sucrose (C12H22O11: MM = 342.2965 g/mol) c) cocaine (C17H21NO4: MM = 303.353 g/mol) d) fructose (C6H12O6: MM = 180.16 g/mol) e) codeine (C18H21 NO3: MM = 299.364 g/mol) been uoy blijow 10e doum wol (3
When 80 mg of an unknown white powder found at a crime scene is dissolved in 1.42 mL of ethan density = 0.789g/mL, normal freezing point -114.6 °C, Kf = 1.99 °C/m), the freezing point is lower -115.6 °C. Which of the following substances could be responsible for this freezing-point depressi (assume the powder is a nonelectrolyte) Show all the work you used to determine the answer. a) meta-tyramine (C8H₁NO: MM = 137.182 g/mol) b) sucrose (C12H22O11: MM = 342.2965 g/mol) c) cocaine (C17H21NO4: MM = 303.353 g/mol) d) fructose (C6H12O6: MM = 180.16 g/mol) e) codeine (C18H21 NO3: MM = 299.364 g/mol) been uoy blijow 10e doum wol (3
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:When 80 mg of an unknown white powder found at a crime scene is dissolved in 1.42 mL of ethand
density = 0.789g/mL, normal freezing point -114.6 °C, Kf = 1.99 °C/m), the freezing point is lowere
-115.6 °C. Which of the following substances could be responsible for this freezing-point depressio
(assume the powder is a nonelectrolyte) Show all the work you used to determine the answer.
a) meta-tyramine (C8H₁₁NO: MM = 137.182 g/mol)
b) sucrose (C12H22O11: MM = 342.2965 g/mol)
c) cocaine (C17H21NO4: MM = 303.353 g/mol)
d) fructose (C6H12O6: MM = 180.16 g/mol)
e) codeine (C18H21 NO3: MM = 299.364 g/mol)
of been uov bluow 10cl doum woh (3
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