None (10 points) In an experiment, a student dissolves 24.6g of LiBr in 0.36kg of solvent. What is themolality of this solution? Show your work.Your Answer:24.6g of LiBr0.36kg solvent.molar mass of LiBr=MM(LiBr) 1x 6.941g/mol + 1x 79.90= 86.841g/molmass of LiBr/Molar mass of LiBr= 24.6/86.841moles-0.2833 molesMoles of solute LiBr/ mass of solevent 0.2833/0.36= 0.78694444 mol/kgWhat is the molality of this solution? 0.79mol/kgANSWER: 1.58 m24.6g LiBrx-1 mol LiBr86.8g-x2mol ions1 mol LiBr0.567 mole LiBr ions0.36kg-=0.567 mol LiBrions€1.575 mLiBr

The problem involves calculating the molality of a solution where 24.6g of LiBr is dissolved in…

Answered: (10 points) In an experiment, a student…

Chemistry

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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H B H cat HCI H₂O
Rank the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest boiling point, choose 2 next to the substance with the next highest boiling point, and so on, substance D HI chemical symbol, chemical formula or Lewis structure H HH ||| HHH Ar H I Ag -0. H H :O: H |||| HICIC-CIH H boiling point (Choose one) (Choose one) (Choose one) (Choose one)
Given the following data: 4C(s) + 4H2(g) + O2(g) → CH3CH2OCOCH3(l) ΔH°=-480.0 kJ CH3CH2OH(l) + O2(g) → CH3COOH(l) + H2O(l) ΔH°=-492.0 kJ 2C(s) + 3H2(g) + 1/2O2(g) → CH3CH2OH(l) ΔH°=-278.0 kJ H2(g) + 1/2O2(g) → H2O(l) ΔH°=-286.0 kJ calculate ΔH° for the reaction:CH3COOH(l) + CH3CH2OH(l) → CH3CH2OCOCH3(l) + H2O(l)
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1. Statement 1: beside its value for jewelries currency and electronics gold is also important in the health profession. Statement 2: Salts of Au+ is used in the treatment of certain types of rheumatoid arthritis2.Statement 1: Cellular restoration allows organisms to liberate the energy stored in the chemical bonds of glucose. Statement 2: C6H12O6 + 6O2 --> 6CO2 + 6H2O + 36 ATP, In this reaction glucose is reduce and oxygen is oxidized.3. Statement 1: The reaction of a metal with either an acid or a metal salt is called displacement reactions because the ion in the solution is to replace through reduction of an element. Statement 2: When metals undergo displacement reactions with acids, salts and hydrogen gas is produced. A - If the first statement is TRUE and the second statement is FALSE B - If the first statement is FALSE and the second statement is TRUE C - If both statements are TRUE D - If both statements are FALSE
[References] Use the References to access important values if needed for this question. Expressing amounts of energy in different energy units is necessary to solve many chemistry problems. For practice, complete the following table. The Joule (J) is the SI unit of energy. 1 calorie (cal) = 4.184 J J cal kJ 568 149 0.807 Submit Answer Try Another Version 10 item attempts remaining pt pt pt Previous Ne re to search DELL
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500.0 mL of 0.100 mol·L HCl(aq) was added to a high quality insulated calorimeter containing 500.0 mL of 0.100 mol·LNaOH(aq). Both solutions had a density of 1.000 g·mL and a specific heat of 4.184 J·g ·K . The calorimeter had a heatcapacity of 850.0 J·K . The temperature of the entire system rose from 25.50 C to 26.05 C.Calculate the heat of reaction. Thank you!
CH3CH2CH2CI c. HNO3 c. H2SO4 KMNO4 AIC13 ОН, heat NH2 СООН NO2 COOH `NO2 CH2CH3 `NH2
510. In an experiment, liquid heptane, C₂H₁6(1), is completely combusted to produce CO₂(g) and H₂O(1), as represented by the following equation. zemina inst C₂H₁6) + 11 O₂(g) →7 CO₂(g) + 8 H₂O(1) The heat of combustion, AH comb, for one mole of C₂H₁6() is -4.85 x 10³ kJ. Determine the enthalpy of formation, AHºf, for C₂H16(1)

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