[References] Use the References to access important values if needed for this question. The boiling point of benzene, Ce He, is 80.10 °C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene Is TNT (trinitrotoluene). A student dissolves 11.96 grams of TNT, C7H5N3O6 (227.1 g/mol), In 261.0 grams of benzene. Use the table of boiling and freezing point constants to answer the questions below. Solvent Kb (°C/m) Kę (°C/m) Water 0.512 1.86 Ethanol 1.22 1.99 Chloroform 3.67 Benzene 2.53 2.02 Formula H₂O CH3 CH₂OH CHC13 C6H6 Diethyl ether CH3 CH₂ OCH₂ CH3 The molality of the solution is The boiling point of the solution is Submit Answer m. °C. 5.12 Retry Entire Group 9 more group attempts remaining
[References] Use the References to access important values if needed for this question. The boiling point of benzene, Ce He, is 80.10 °C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene Is TNT (trinitrotoluene). A student dissolves 11.96 grams of TNT, C7H5N3O6 (227.1 g/mol), In 261.0 grams of benzene. Use the table of boiling and freezing point constants to answer the questions below. Solvent Kb (°C/m) Kę (°C/m) Water 0.512 1.86 Ethanol 1.22 1.99 Chloroform 3.67 Benzene 2.53 2.02 Formula H₂O CH3 CH₂OH CHC13 C6H6 Diethyl ether CH3 CH₂ OCH₂ CH3 The molality of the solution is The boiling point of the solution is Submit Answer m. °C. 5.12 Retry Entire Group 9 more group attempts remaining
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![[References]
Use the References to access important values if needed for this question.
The boiling point of benzene, Ce He, is 80.10 °C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene
Is TNT (trinitrotoluene).
A student dissolves 11.96 grams of TNT, C7H5N3O6 (227.1 g/mol), In 261.0 grams of benzene. Use the table of boiling
and freezing point constants to answer the questions below.
Solvent
Kb (°C/m) K₁ (°C/m)
Water
0.512
1.86
Ethanol
1.22
1.99
Chloroform
3.67
Benzene
2.53
2.02
Formula
H₂O
CH3CH₂OH
CHC13
C6H6
Diethyl ether CH3 CH₂ OCH₂ CH3
The molality of the solution is
The boiling point of the solution is
Submit Answer
m.
Show Hint
°C.
Retry Entire Group 9 more group attempts remaining
5.12
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Transcribed Image Text:[References]
Use the References to access important values if needed for this question.
The boiling point of benzene, Ce He, is 80.10 °C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene
Is TNT (trinitrotoluene).
A student dissolves 11.96 grams of TNT, C7H5N3O6 (227.1 g/mol), In 261.0 grams of benzene. Use the table of boiling
and freezing point constants to answer the questions below.
Solvent
Kb (°C/m) K₁ (°C/m)
Water
0.512
1.86
Ethanol
1.22
1.99
Chloroform
3.67
Benzene
2.53
2.02
Formula
H₂O
CH3CH₂OH
CHC13
C6H6
Diethyl ether CH3 CH₂ OCH₂ CH3
The molality of the solution is
The boiling point of the solution is
Submit Answer
m.
Show Hint
°C.
Retry Entire Group 9 more group attempts remaining
5.12
Cengage Learning Cengage Technical Support
MacBook Air
Previous Next>
Save and Exit
Expert Solution
Step 1
Given,
mass of TNT (trinitrotoluene) = 11.96 g
Molar mass of TNT (trinitrotoluene) = 227.1 g/mol
Mass of benzene solvent = 261.0 g = 0.261 kg
Kb for benzene = 2.53 °C/m
Boiling point of benzene (Tb(benzene)) = 80.10 °C
molality of the solution = ? m
Boiling point of the solution = ? °C
Note:
van't Hoff factor for TNT (trinitrotoluene) = 1
(TNT is a nonelectrolyte, nonvolatile solute)
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