Chrome File Edit View History Bookmarks Profiles Tab Window Help41% ¹OO AP OneStop Austin Peay State Uni x D21 Grades - Radiologic Technolog x W Physics 2020-W4 & W1B/202 X PHYS 2020 Class 19 Homework X← → C webassign.net/web/Student/Assignment-Responses/tutorial?dep=29005163&tags=autosave#question4270878_0Sun May 1 9:44:52 PM Allie Privitt QW PHYS 2020 Class 21 Homework x +M* ■Error UpdateThis question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.Tutorial ExerciseA 1.00-cm-high object is placed 3.88 cm to the left of a converging lens of focal length 8.13 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. Is the image inverted or upright? Is the image real or virtual?Step 1The 1.00-cm-high object serves as a real object, located at a distance p₁ = 3.88 cm in front of the converging lens L₁, as shown in the diagram.FigureUpper DiagramLower DiagramL****F₂O₂=1₁P₂4Let f₁ be the focal length of the converging lens. The thin lens equation gives the image distance for this lens asP₁f₁91=cm²)cmcm.Submit Skip (you cannot come back)SIDWtvA4hNeed Help? Read ItitSubmit Answer0₁-1911Pi-6.00 cmMagacmMAYP

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Answered: A 1.00-cm-high object is placed 3.88 cm…

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