A 0.547 g sample of an unknown solute dissolved in 14.0 g of tert-butanol produces a solution with a freezing point of 22.70 °C. What is the molar mass of the solute? For tert-butanol T; = 25.50 °C, kf = 9.10 °C · kg · mol-!. molar mass = g/mol

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A 0.547 g sample of an unknown solute dissolved in 14.0 g of tert-butanol produces a solution with a freezing point of
22.70 °C. What is the molar mass of the solute?
For tert-butanol T = 25.50 °C, kf = 9.10 °C · kg · mol-.
molar mass =
g/mol
Transcribed Image Text:A 0.547 g sample of an unknown solute dissolved in 14.0 g of tert-butanol produces a solution with a freezing point of 22.70 °C. What is the molar mass of the solute? For tert-butanol T = 25.50 °C, kf = 9.10 °C · kg · mol-. molar mass = g/mol
Expert Solution
Step 1

At a specific temperature, when vapor pressure of any particular substance in its liquid and solid phase becomes equivalent or merge at a point, then this point is basically designated as the freezing point.

If the temperature measured after adding  solute to a particular solvent decreases then this decrease is the depression in its freezing point.

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