The normal boiling point of a certain liquid X is 121.00 °C, but when 0.12 kg of benzamide (C,H,NO) are dissolved in 800. g of X the solution boils at 122.9 °C instead. Use this information to calculate the molal boiling point elevation constant K, of X. Be sure your answer is rounded to the correct number of significiant digits. °C·kg K, = 0 mol

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Chapter1: Chemical Foundations
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**Problem Statement:**

The normal boiling point of a certain liquid \( X \) is 121.00 °C, but when 0.12 kg of benzamide (C\(_7\)H\(_7\)NO) are dissolved in 800. g of \( X \), the solution boils at 122.9 °C instead. Use this information to calculate the molal boiling point elevation constant \( K_b \) of \( X \).

Be sure your answer is rounded to the correct number of significant digits.

**Equation Box:**

\[ K_b = \frac{\text{°C} \cdot \text{kg}}{\text{mol}} \]

**Input Box:**

There is an input box for the answer next to buttons for submit, reset, and help.
Transcribed Image Text:**Problem Statement:** The normal boiling point of a certain liquid \( X \) is 121.00 °C, but when 0.12 kg of benzamide (C\(_7\)H\(_7\)NO) are dissolved in 800. g of \( X \), the solution boils at 122.9 °C instead. Use this information to calculate the molal boiling point elevation constant \( K_b \) of \( X \). Be sure your answer is rounded to the correct number of significant digits. **Equation Box:** \[ K_b = \frac{\text{°C} \cdot \text{kg}}{\text{mol}} \] **Input Box:** There is an input box for the answer next to buttons for submit, reset, and help.
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