A 0.27 kg particle moves in an xy plane according to x(t) = - 11+2 t-6 t³ and y(t) = 17 + 7 t-9 t2, with x and y in meters and t in seconds. At t = 1.0 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?

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A 0.27 kg particle moves in an xy plane according to x(t) = - 11+2 t-6 t³ and y(t) = 17 + 7 t - 9 t², with x and y in meters and t in seconds.
At t = 1.0 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of
the net force on the particle, and (c) what is the angle of the particle's direction of travel?
Transcribed Image Text:A 0.27 kg particle moves in an xy plane according to x(t) = - 11+2 t-6 t³ and y(t) = 17 + 7 t - 9 t², with x and y in meters and t in seconds. At t = 1.0 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
There are two forces on the 1.14 kg box in the overhead view of the figure but only one is shown. For F₁ = 17.5 N, a = 12.1 m/s2, and 0 =
38.9°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle
measured from the +x direction.)
x
Transcribed Image Text:There are two forces on the 1.14 kg box in the overhead view of the figure but only one is shown. For F₁ = 17.5 N, a = 12.1 m/s2, and 0 = 38.9°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.) x
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