Two 2.5-cm-diameter-disks spaced 2.0 mm apart form a parallel- plate capacitor. The electric field between the disks is 5.0×105 V/m. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. ✓ ▾ Part B Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. How much charge is on each disk? Express your answers in coulombs separated by a comma 91-92 22x109.-2.2×10-9 C Part C ✓ Correct U iaital = Previous Answers Previous Answers An electron launched from the negative plate. It strikes the positive plate at a speed of 2.5x10 m/s. What was the electron's speed as it left the negative plate? Express your answer with the appropriate units. Submit I xa μA Xp Value 7 • . x 10m Xx Units www. ? Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining M

College Physics
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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Need help with part c please.
**Educational Content: Parallel-Plate Capacitor Problem**

**Problem Statement:**

Two 2.5-cm-diameter disks spaced 2.0 mm apart form a parallel-plate capacitor. The electric field between the disks is \(5.0 \times 10^5 \, \text{V/m}\).

For the steps and strategies involved in solving a similar problem, you may view a [Video Tutor Solution](#).

---

**Solution Details:**

**Part B:**

- Question: How much charge is on each disk?
  
- Answer Format: Express your answers in coulombs separated by a comma.

  \[
  q_1, \, q_2 = 2.2 \times 10^{-9}, \, -2.2 \times 10^{-9} \, \text{C}
  \]

- Status: Correct

---

**Part C:**

- Scenario: An electron is launched from the negative plate. It strikes the positive plate at a speed of \(2.5 \times 10^7 \, \text{m/s}\). What was the electron’s speed as it left the negative plate?

- Answer Format: Express your answer with the appropriate units.

  - *Answer Box*: [Value] [Units]

- Status: Incorrect. (Feedback: Try Again; 5 attempts remaining)

---

**Guidance for Students:**

- Remember to use the full unrounded value in your calculations to ensure accuracy where specified.
  
- Always express your answers with the correct units following scientific notation standards.

---
Transcribed Image Text:**Educational Content: Parallel-Plate Capacitor Problem** **Problem Statement:** Two 2.5-cm-diameter disks spaced 2.0 mm apart form a parallel-plate capacitor. The electric field between the disks is \(5.0 \times 10^5 \, \text{V/m}\). For the steps and strategies involved in solving a similar problem, you may view a [Video Tutor Solution](#). --- **Solution Details:** **Part B:** - Question: How much charge is on each disk? - Answer Format: Express your answers in coulombs separated by a comma. \[ q_1, \, q_2 = 2.2 \times 10^{-9}, \, -2.2 \times 10^{-9} \, \text{C} \] - Status: Correct --- **Part C:** - Scenario: An electron is launched from the negative plate. It strikes the positive plate at a speed of \(2.5 \times 10^7 \, \text{m/s}\). What was the electron’s speed as it left the negative plate? - Answer Format: Express your answer with the appropriate units. - *Answer Box*: [Value] [Units] - Status: Incorrect. (Feedback: Try Again; 5 attempts remaining) --- **Guidance for Students:** - Remember to use the full unrounded value in your calculations to ensure accuracy where specified. - Always express your answers with the correct units following scientific notation standards. ---
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