A 0.0715 g sample of a material was analyzed for thiourea(CS(NH2)2, MM = 76.12). It was found to consume 24.68 mL of0.00543 M KBRO3 based on the reaction below:3CS(NH2)2 + 4BRO, + 3H20 2 3CO(NH2)2 + 3SO, +4Br + 6H*Calculate the mass of thiourea found in the sample.O 10.7 mgО 190 mgO 13.6 mgO 7.65 mg

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A 0.0715 g sample of a material was analyzed for thiourea (CS(NH2)2, MM = 76.12). It was found to consume 24.68 mL of 0.00543 M KBrOz based on the reaction below: %3D 3CS(NH2)2 + 4BRO3 + 3H20 2 3CO(NH2)2 + 3SO2 + 4Br + 6H* Calculate the mass of thiourea found in the sample. O 10.7 mg O 190 mg O 13.6 mg O 7.65 mg

A 0.0715 g sample of a material was analyzed for thiourea (CS(NH2)2, MM = 76.12). It was found to consume 24.68 mL of 0.00543 M KBrOz based on the reaction below: %3D 3CS(NH2)2 + 4BRO3 + 3H20 2 3CO(NH2)2 + 3SO2 + 4Br + 6H* Calculate the mass of thiourea found in the sample. O 10.7 mg O 190 mg O 13.6 mg O 7.65 mg

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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