5. What is the maximum amount of water that can be obtained from 22.05 g of copper and 750.00 mL of 1.00 M of nitric acid according to the below reaction? 3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H20(t)

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Chapter1: Chemical Foundations
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AaBbCcDdF
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AaBbCcDdE AaBbCcAaBbCcDdE
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5. What is the maximum amount of water that can be obtained from 22.05 g of copper and
750.00 mL of 1.00 M of nitric acid according to the below reaction?
3 Cu(s) + 8 HNO3(aq)
3 Cu(NO3)2(aq) + 2 NO(g) + 4 H20(t)
6. If 25.00 mL of 2.11x10-8 M Na2SO4 is mixed with 20.00 mL of 1.22x10-8 M Ba(NO3)2,
how many grams of precipitate (which is?) can be formed?
7. In all the limiting reactant questions, how much of the excess reactant is left over? Give
answer in mass or volume as appropriate.
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Transcribed Image Text:AaBbCcDdF 三 斗 T AaBbCcDdE AaBbCcAaBbCcDdE Aa v Normal Strong Emphasis Heading 1 v A v 5. What is the maximum amount of water that can be obtained from 22.05 g of copper and 750.00 mL of 1.00 M of nitric acid according to the below reaction? 3 Cu(s) + 8 HNO3(aq) 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H20(t) 6. If 25.00 mL of 2.11x10-8 M Na2SO4 is mixed with 20.00 mL of 1.22x10-8 M Ba(NO3)2, how many grams of precipitate (which is?) can be formed? 7. In all the limiting reactant questions, how much of the excess reactant is left over? Give answer in mass or volume as appropriate. English United States O Focus MacBook Air 吕口 F3 000 FA F2 * ES > F6 F7 FB F9 F10 $4 & 4 6. 7 8 5 III III %#3 |II lili
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