1. How many grams of solid product can be produced from adding 156 ml of .425M silver nitrate solution to excess sodium phosphate solution? 3 AgNO3 0.425 L 156m1 0.150 (@g + назрь саду → Адзроч (S) + → Agapoy (S) + 3 NaNO3(aq) mole L 6.156 L x 0.425 = 0.0063 mole (6.063 mole AgNO3)( mole of Agz poy (3 mole of Ag No 3/ = 0.0221 mol - = 9.259 2. What volume in milliliters of .645M sodium phosphate solution would be needed to completely react with the above amount of silver nitrate? 0.0221 more - 418.6 g/mot . 645 M Na 3 PO 40 156 ml of 425 M AgNO3 Naz Poy Na Ng + Agos 0.0221 molarity = 17 6.643 m = 6.1343 = 24.4 3. How many milliliters of .645M sodium phosphate would a student need to produce 67.8 grams of silver phosphate if he could use excess silver nitrate solution?

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Worksheet #18
1. How many grams of solid product can be produced from adding 156 ml of .425M
silver nitrate solution to excess sodium phosphate solution?
3 AgNO3
+ Naz po 4(aq) → Agapoy (S) + 3 NaNO3(aq)
V=
0.425 L
156m1
0.156 L
6.156 L x 0.425
= 0.0663 mole
(6.063 mole AgNO3)( mole of Agz poy
3 moleq AgNO3/
= 0.0221 mol
0.0221 mole
= 9.259
418.6 g/mol
2. What volume in milliliters of .645M sodium phosphate solution would be needed
to completely react with the above amount of silver nitrate?
645 M Na3PO4/0
n
mole
L
156 ml of 425 M AgNO3
Naz Poy
.
Na Ng + Ag!
0.02211
643 m
polarity
= 6.0343 L
3. How many milliliters of .645M sodium phosphate would a student need to
produce 67.8 grams of silver phosphate if he could use excess silver nitrate
solution?
17 27 (67.29 154/teak hastay
*)
Mag Agatis
210 44
$14
Ink Agatay mile 110
Inie nasto
Transcribed Image Text:Worksheet #18 1. How many grams of solid product can be produced from adding 156 ml of .425M silver nitrate solution to excess sodium phosphate solution? 3 AgNO3 + Naz po 4(aq) → Agapoy (S) + 3 NaNO3(aq) V= 0.425 L 156m1 0.156 L 6.156 L x 0.425 = 0.0663 mole (6.063 mole AgNO3)( mole of Agz poy 3 moleq AgNO3/ = 0.0221 mol 0.0221 mole = 9.259 418.6 g/mol 2. What volume in milliliters of .645M sodium phosphate solution would be needed to completely react with the above amount of silver nitrate? 645 M Na3PO4/0 n mole L 156 ml of 425 M AgNO3 Naz Poy . Na Ng + Ag! 0.02211 643 m polarity = 6.0343 L 3. How many milliliters of .645M sodium phosphate would a student need to produce 67.8 grams of silver phosphate if he could use excess silver nitrate solution? 17 27 (67.29 154/teak hastay *) Mag Agatis 210 44 $14 Ink Agatay mile 110 Inie nasto
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