1. How many grams of solid product can be produced from adding 156 ml of .425M silver nitrate solution to excess sodium phosphate solution? 3 AgNO3 0.425 L 156m1 0.150 (@g + назрь саду → Адзроч (S) + → Agapoy (S) + 3 NaNO3(aq) mole L 6.156 L x 0.425 = 0.0063 mole (6.063 mole AgNO3)( mole of Agz poy (3 mole of Ag No 3/ = 0.0221 mol - = 9.259 2. What volume in milliliters of .645M sodium phosphate solution would be needed to completely react with the above amount of silver nitrate? 0.0221 more - 418.6 g/mot . 645 M Na 3 PO 40 156 ml of 425 M AgNO3 Naz Poy Na Ng + Agos 0.0221 molarity = 17 6.643 m = 6.1343 = 24.4 3. How many milliliters of .645M sodium phosphate would a student need to produce 67.8 grams of silver phosphate if he could use excess silver nitrate solution?
1. How many grams of solid product can be produced from adding 156 ml of .425M silver nitrate solution to excess sodium phosphate solution? 3 AgNO3 0.425 L 156m1 0.150 (@g + назрь саду → Адзроч (S) + → Agapoy (S) + 3 NaNO3(aq) mole L 6.156 L x 0.425 = 0.0063 mole (6.063 mole AgNO3)( mole of Agz poy (3 mole of Ag No 3/ = 0.0221 mol - = 9.259 2. What volume in milliliters of .645M sodium phosphate solution would be needed to completely react with the above amount of silver nitrate? 0.0221 more - 418.6 g/mot . 645 M Na 3 PO 40 156 ml of 425 M AgNO3 Naz Poy Na Ng + Agos 0.0221 molarity = 17 6.643 m = 6.1343 = 24.4 3. How many milliliters of .645M sodium phosphate would a student need to produce 67.8 grams of silver phosphate if he could use excess silver nitrate solution?
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
Transcribed Image Text:Worksheet #18
1. How many grams of solid product can be produced from adding 156 ml of .425M
silver nitrate solution to excess sodium phosphate solution?
3 AgNO3
+ Naz po 4(aq) → Agapoy (S) + 3 NaNO3(aq)
V=
0.425 L
156m1
0.156 L
6.156 L x 0.425
= 0.0663 mole
(6.063 mole AgNO3)( mole of Agz poy
3 moleq AgNO3/
= 0.0221 mol
0.0221 mole
= 9.259
418.6 g/mol
2. What volume in milliliters of .645M sodium phosphate solution would be needed
to completely react with the above amount of silver nitrate?
645 M Na3PO4/0
n
mole
L
156 ml of 425 M AgNO3
Naz Poy
.
Na Ng + Ag!
0.02211
643 m
polarity
= 6.0343 L
3. How many milliliters of .645M sodium phosphate would a student need to
produce 67.8 grams of silver phosphate if he could use excess silver nitrate
solution?
17 27 (67.29 154/teak hastay
*)
Mag Agatis
210 44
$14
Ink Agatay mile 110
Inie nasto
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