I am getting stuck with finding the mols, grams and percent of Cr^3+. by MonSubnitNameDatePreparation and Analysis of a Purple Nickel CompoundPrelab2.0184 g of a compound of the general formula Crx(NH3),Clz was prepared using 3.5246 g CrCl36 H2O and 10.00 mL of 15 M NH3. It was then analyzed as follows:Analysis of Cr3+The concentration of Cr³* was determined spectrophotometrically. The chromium(III) ion ispurple, with a maximum light absorption at 570 nm. A stock solution (Solution 1) of 0.100 MCr* was used to make the following dilutions:Solution 2: 10.00 mL stock solution diluted to a total volume of 100 mL with water.Solution 3: 20.00 mL stock solution diluted to a total volume of 100 mL with water.1.2532 g of the unknown chromium compound was dissolved in enough water to make 100 mLof solution. Absorbance readings are given below:34Solution 20.100M(10MC)=X 10omlX= 0.01MColution 3AbsorbanceConcentration0:1com0.01M0.02M0.06mCalculate the concentration of Cr** in solutions 2 and 3, Then, make a graph of absorbance vs.concentration using the three known (standard) solutions. From the graph, find the concentrationof the chromium compound, calculate moles of Cr³*, grams of Cr³*, and % Cr³* in the unknownSolution1.85010.1870.37431.122unknown compoundcompound. Attach graph and show work below.3t 6.00mol0.0GM OFAnswers:0.0GMmol/L Cr* (from graph)mol Cr+g Cr3+% Cr+shot on moto g' powerCrystal H.73

Solution 2 is a 1:10 dilution of solution one. Its concentration is 0.1M /10 = 0.0100 M Solution 3…

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I am getting stuck with finding the mols, grams and percent of Cr^3+

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter26: Molecular Absorption Spectrometry

Section: Chapter Questions

Problem 26.31QAP

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

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I am getting stuck with finding the mols, grams and percent of Cr^3+.

by Mon
Subnit
Name
Date
Preparation and Analysis of a Purple Nickel Compound
Prelab
2.0184 g of a compound of the general formula Crx(NH3),Clz was prepared using 3.5246 g CrCl3
6 H2O and 10.00 mL of 15 M NH3. It was then analyzed as follows:
Analysis of Cr3+
The concentration of Cr³* was determined spectrophotometrically. The chromium(III) ion is
purple, with a maximum light absorption at 570 nm. A stock solution (Solution 1) of 0.100 M
Cr* was used to make the following dilutions:
Solution 2: 10.00 mL stock solution diluted to a total volume of 100 mL with water.
Solution 3: 20.00 mL stock solution diluted to a total volume of 100 mL with water.
1.2532 g of the unknown chromium compound was dissolved in enough water to make 100 mL
of solution. Absorbance readings are given below:
34
Solution 2
0.100M(10MC)=X 10oml
X= 0.01M
Colution 3
Absorbance
Concentration
0:1com
0.01M
0.02M
0.06m
Calculate the concentration of Cr** in solutions 2 and 3, Then, make a graph of absorbance vs.
concentration using the three known (standard) solutions. From the graph, find the concentration
of the chromium compound, calculate moles of Cr³*, grams of Cr³*, and % Cr³* in the unknown
Solution
1.850
1
0.187
0.374
3
1.122
unknown compound
compound. Attach graph and show work below.
3t 6.00mol
0.0GM OF
Answers:
0.0GM
mol/L Cr* (from graph)
mol Cr+
g Cr3+
% Cr+
shot on moto g' power
Crystal H.
73

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