9.a. Circle all the appropriate terms. Cl x= Me Cl t-Bu- The two molecules drawn above are enantiomers optically active enantiomers superimposable 9.b. Circle all the appropriate terms. diastereomers not optically active H H₂C Br optically active Bull.... -CH3 The two molecules drawn above are H diastereomers not optically active superimposable Me chiral meso not superimposable H₂C H ...ill Br chiral meso H CH₂ Br not superimposable Cl achiral t-Bu identical achiral identical a

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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9.a. Circle all the appropriate terms.
t-Bu
The two molecules drawn above are
enantiomers
optically active
enantiomers
superimposable
9.b. Circle all the appropriate terms.
diastereomers
not optically active
H
optically active
Bull....
H₂CH...
Br
-CH3
The two molecules drawn above are
Me
H
diastereomers
not optically active
superimposable
Me
chiral
meso
not superimposable
H3C-
H
.......
chiral
meso
H
...III\CH3
Br
not superimposable
Cl
achiral
-t-Bu
identical
achiral
identical
3
Transcribed Image Text:9.a. Circle all the appropriate terms. t-Bu The two molecules drawn above are enantiomers optically active enantiomers superimposable 9.b. Circle all the appropriate terms. diastereomers not optically active H optically active Bull.... H₂CH... Br -CH3 The two molecules drawn above are Me H diastereomers not optically active superimposable Me chiral meso not superimposable H3C- H ....... chiral meso H ...III\CH3 Br not superimposable Cl achiral -t-Bu identical achiral identical 3
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