9. Using the formula for the energy levels of the Morse potential, (hv) ² (v + 1½-2)² E₁ = hv (v + 1 ) = ( hv) ² Ev - 4De Show that the energy level spacing between adjacent levels is given by (hv)² - Ev+1 — E₁ = hv - − Ev (v + 1) For ¹H35C1, De == 7.41 × 10-19 J and v = 8.97 × 1013 Hz. Calculate the smallest value of v for which E₁+1 - Ev < 0.5(E₁ - Eo). 2De
9. Using the formula for the energy levels of the Morse potential, (hv) ² (v + 1½-2)² E₁ = hv (v + 1 ) = ( hv) ² Ev - 4De Show that the energy level spacing between adjacent levels is given by (hv)² - Ev+1 — E₁ = hv - − Ev (v + 1) For ¹H35C1, De == 7.41 × 10-19 J and v = 8.97 × 1013 Hz. Calculate the smallest value of v for which E₁+1 - Ev < 0.5(E₁ - Eo). 2De
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter15: Introduction To Electronic Spectroscopy And Structure
Section: Chapter Questions
Problem 15.56E
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![9. Using the formula for the energy levels of the Morse potential,
(hv) ² (v + 1½-2)²
E₁ = hv (v + 1 ) = ( hv) ²
Ev
-
4De
Show that the energy level spacing between adjacent levels is given by
(hv)²
-
Ev+1 — E₁ = hv -
− Ev
(v + 1)
For ¹H35C1, De
==
7.41 × 10-19 J and v = 8.97 × 1013 Hz. Calculate the smallest value of v
for which E₁+1 - Ev < 0.5(E₁ - Eo).
2De](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F95ea96fb-17c9-4f05-b9b8-3431ba2409f6%2F20c7b3cf-cd07-4856-8a5d-a6f5fd39ac55%2F2pdny58_processed.png&w=3840&q=75)
Transcribed Image Text:9. Using the formula for the energy levels of the Morse potential,
(hv) ² (v + 1½-2)²
E₁ = hv (v + 1 ) = ( hv) ²
Ev
-
4De
Show that the energy level spacing between adjacent levels is given by
(hv)²
-
Ev+1 — E₁ = hv -
− Ev
(v + 1)
For ¹H35C1, De
==
7.41 × 10-19 J and v = 8.97 × 1013 Hz. Calculate the smallest value of v
for which E₁+1 - Ev < 0.5(E₁ - Eo).
2De
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