9 0.02m 1.3 m k = 0.35 mic Lw Lins Reins Kins Ains Ts=30°C W q" = 1830 771 Ts. = 1300°C Ts.2 Solution AT Ts1-T83 Ts1 - TS3 Ts1 - Ts2 =A = A 9 ΣR Lw Lins Lw Lins Low + + KwAw KinsAins kw Kins kw q= 1 AT AΣRE W T1 TS3 Ts1 Ts Ts1 - Ts2 Ts2 - Ts3 1830 m2 Love Lins Lins + Kins kw Kins W 1830 m2 + kw kins Ts1-Ts3 Iw Lins Lins = kins (Ts1 Ts3) 1830 W m2 W W m² kw = 0.2375m 1830 rect Question 8 0/1 pts For the previous problem, determine the temperature at the junction of the wall and insulation (in degrees C)
9 0.02m 1.3 m k = 0.35 mic Lw Lins Reins Kins Ains Ts=30°C W q" = 1830 771 Ts. = 1300°C Ts.2 Solution AT Ts1-T83 Ts1 - TS3 Ts1 - Ts2 =A = A 9 ΣR Lw Lins Lw Lins Low + + KwAw KinsAins kw Kins kw q= 1 AT AΣRE W T1 TS3 Ts1 Ts Ts1 - Ts2 Ts2 - Ts3 1830 m2 Love Lins Lins + Kins kw Kins W 1830 m2 + kw kins Ts1-Ts3 Iw Lins Lins = kins (Ts1 Ts3) 1830 W m2 W W m² kw = 0.2375m 1830 rect Question 8 0/1 pts For the previous problem, determine the temperature at the junction of the wall and insulation (in degrees C)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
work from previous problem please answer question 8
![9
0.02m
1.3
m
k = 0.35
mic
Lw
Lins
Reins
Kins Ains
Ts=30°C
W
q" = 1830
771
Ts. = 1300°C
Ts.2
Solution
AT
Ts1-T83
Ts1 - TS3
Ts1 - Ts2
=A
= A
9
ΣR
Lw
Lins
Lw
Lins
Low
+
+
KwAw KinsAins
kw
Kins
kw
q=
1 AT
AΣRE
W T1
TS3
Ts1 Ts
Ts1 - Ts2
Ts2 - Ts3
1830
m2
Love
Lins
Lins
+
Kins
kw
Kins
W
1830
m2
+
kw kins
Ts1-Ts3
Iw Lins
Lins = kins
(Ts1 Ts3) 1830
W
m2
W W
m² kw = 0.2375m
1830
rect
Question 8
0/1 pts
For the previous problem, determine the temperature at the junction of the wall
and insulation (in degrees C)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b36aceb-991d-4e2d-8577-6c034d40c9f6%2F989e2cfb-9ed1-477e-8968-fc78d275f443%2F5pa72o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9
0.02m
1.3
m
k = 0.35
mic
Lw
Lins
Reins
Kins Ains
Ts=30°C
W
q" = 1830
771
Ts. = 1300°C
Ts.2
Solution
AT
Ts1-T83
Ts1 - TS3
Ts1 - Ts2
=A
= A
9
ΣR
Lw
Lins
Lw
Lins
Low
+
+
KwAw KinsAins
kw
Kins
kw
q=
1 AT
AΣRE
W T1
TS3
Ts1 Ts
Ts1 - Ts2
Ts2 - Ts3
1830
m2
Love
Lins
Lins
+
Kins
kw
Kins
W
1830
m2
+
kw kins
Ts1-Ts3
Iw Lins
Lins = kins
(Ts1 Ts3) 1830
W
m2
W W
m² kw = 0.2375m
1830
rect
Question 8
0/1 pts
For the previous problem, determine the temperature at the junction of the wall
and insulation (in degrees C)
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