8 (L{Lun(t)}) = 8 (sm L{un(t)} – sm-¹un (0) - ... -u (m-1) ( = s™ 8 (L{un(t)}). Therefore, we get (0)) L{λ(t)} sm Therefore, we have the following iteration algorithm: 1 (m). L{un+1(t)} = L{un(t)} - L{L(m³ un(t) + R un(t) + N un(t) − 9 ; g(t)} sm (m). - = L{un(t)}-{Lun(t)}- L{Run(t) + Nun(t) − g(t)} = L{un(t)} - - sm sm sm (sm L{un(t)}-sm-un (0) L{Run(t) + Nun(t) − g(t)} -um-1) (0)) · + (0) %/n 2 + (0) ³n == ամ 1 (m-1) + sm Un '(0) - 1 sm L{Run(t) + Nun(t) − g(t)} Finally, the approximate solution is given by u(x,t) = lim un(x,t) 12-00 to solve the following partial differential equations: E u₁+uuxuxx, u(x, 0) = x, 00 00

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.3: Algebraic Expressions
Problem 5E
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This picture shows the simplifying steps of how to derive the Laplace variational lteration method with the same steps and the same method. Please derive the Elzaki variational lteration method. and then solve the equation below in this new way.
8 (L{Lun(t)}) = 8 (sm L{un(t)} – sm-¹un (0) - ... -u (m-1) (
= s™ 8 (L{un(t)}).
Therefore, we get
(0))
L{λ(t)}
sm
Therefore, we have the following iteration algorithm:
1
(m).
L{un+1(t)} = L{un(t)} - L{L(m³ un(t) + R un(t) + N un(t) − 9
; g(t)}
sm
(m).
-
= L{un(t)}-{Lun(t)}- L{Run(t) + Nun(t) − g(t)}
= L{un(t)}
-
-
sm
sm
sm
(sm L{un(t)}-sm-un (0)
L{Run(t) + Nun(t) − g(t)}
-um-1) (0))
· + (0) %/n 2 + (0) ³n ==
ամ
1
(m-1)
+
sm
Un
'(0)
-
1
sm
L{Run(t) + Nun(t) − g(t)}
Finally, the approximate solution is given by
u(x,t) = lim un(x,t)
12-00
to solve the following partial differential equations:
E
u₁+uuxuxx, u(x, 0) = x,
00
00
Transcribed Image Text:8 (L{Lun(t)}) = 8 (sm L{un(t)} – sm-¹un (0) - ... -u (m-1) ( = s™ 8 (L{un(t)}). Therefore, we get (0)) L{λ(t)} sm Therefore, we have the following iteration algorithm: 1 (m). L{un+1(t)} = L{un(t)} - L{L(m³ un(t) + R un(t) + N un(t) − 9 ; g(t)} sm (m). - = L{un(t)}-{Lun(t)}- L{Run(t) + Nun(t) − g(t)} = L{un(t)} - - sm sm sm (sm L{un(t)}-sm-un (0) L{Run(t) + Nun(t) − g(t)} -um-1) (0)) · + (0) %/n 2 + (0) ³n == ամ 1 (m-1) + sm Un '(0) - 1 sm L{Run(t) + Nun(t) − g(t)} Finally, the approximate solution is given by u(x,t) = lim un(x,t) 12-00 to solve the following partial differential equations: E u₁+uuxuxx, u(x, 0) = x, 00 00
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