y"-3y" +3y-y= (241 - 12)e' 2. Use the method of variation of parameters to find the general solution of the linear equation. y"-3y"-y+3y= 9t
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- Suppose you are climbing a hill whose shape is given by the equation z = 1,300 − 0.005x2 − 0.01y2, where x, y, and z are measured in meters, and you are standing at a point with coordinates (80, 80, 1204). The positive x-axis points east and the positive y-axis points north.Solve using variation of parameters. Choose the correct answer from the choices. A. y = C1et + C2(t +1) - t2 - 2t - 2 B. y = C1et + C2 - t2 Handwritten answer.Solve for the solution for the equation: (2x²y – 2x³) + (4x³ – 6x²y + 2xy²)y' = 0 with the condition of y(1) = 3.
- (y2-2xy-x2)dx+(2x2)dy Find the solution of the equation through the point (1,2)5x 18 1.Solve for x: x-4 x² - 3x +2, x -x x² - 4 2 .Divide : x' + 2x and write the answer in simplest form 3. Find the equation of the line that is perpendicular to the line passing through the points (-10,12) and (-1, 7) and passes through (-25,-8).Solve ў + бў+9у — 0 dy + 2y = e-4 dx d²y dx2 + y = 0