If f : R → R is a function defined by f(x) = [x − 1] cos (2221) π, where [.] denotes the greatest integer function, then f is: (1) discontinuous only at x = 1 (2) discontinuous at all integral values of x except at x = 1 (3) continuous only at x = 1 (4) continuous for every real x
If f : R → R is a function defined by f(x) = [x − 1] cos (2221) π, where [.] denotes the greatest integer function, then f is: (1) discontinuous only at x = 1 (2) discontinuous at all integral values of x except at x = 1 (3) continuous only at x = 1 (4) continuous for every real x
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter5: Rings, Integral Domains, And Fields
Section5.4: Ordered Integral Domains
Problem 5E: 5. Prove that the equation has no solution in an ordered integral domain.
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![If f : R → R is a function defined by f(x) = [x − 1] cos (2221) π, where [.] denotes the greatest
integer function, then f is:
(1) discontinuous only at x = 1
(2) discontinuous at all integral values of x except at x = 1
(3) continuous only at x =
1
(4) continuous for every real x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fa2faeb-8a3b-4253-8dd2-c4b3c0abed23%2Fc1bca858-1a09-4099-a704-f879e8fd017a%2Fu6j7woc_processed.png&w=3840&q=75)
Transcribed Image Text:If f : R → R is a function defined by f(x) = [x − 1] cos (2221) π, where [.] denotes the greatest
integer function, then f is:
(1) discontinuous only at x = 1
(2) discontinuous at all integral values of x except at x = 1
(3) continuous only at x =
1
(4) continuous for every real x
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