v(x,y Using RDTM to solve the following styem (3) UV-24+ ( ) at av бу ot v (x,y,t) = U - ܲ √ + /1/17 ( 4(x14, 0) = ex-y - V (x 4,0) = x+y dx² + Uk (X) + UK (x) = 0.

Determine y'of (3x + 1)ª(2x – 1)³

When you substitute y''p and yp into the equation, where does the: 4Ccos(2x) and -4Dsin(2x) come from? While you have 10 different trig functions from the substitution, there should only have been 8 trig finctions from the substitution.... y'' = -9Asin(3x) - 9Bcos(3x) - 4Csin(2x) - 4Dcos(2x) --> that's 4 and 4y = 4(Asin(3x) + Bcos(3x) +Csin(2x) + Dcos(2x)) --> that's the other 4. Where does the 4Ccos(2x) and -4Dsin(2x) come from in the multiplication?