#71 12. Use your answers for Questions 4 and 10 to calculate [SCN -] q, the equilbrium concentration of SCN-, for the Test Tube 3 reaction mixture described in Question 10. [FeSCN³¹] Initial Change Equilibrium [Fe³] Q1 answer (0.0010) -x (0.0000749) Q11 answer (0.00093) = [SCN -]q, Q4 answer - x 201 [SCN-] Q4 answer (0.00060) -x (0.0000749) Q12 answer (0.00053) +x x=Q10 answer (0.0000749) blano OH to Jm 0.S+ иоx M 900.0 to Jm 13. What is the calculated value of Kc for the Test Tube 3 reaction mixture described in Question 10? To answer this Question, you will need to plug your answers for Questions 10, 11, and 12 into the expression for Kc, which you identified if you correctly answered Question 7. K. = [FeSCN 2+]/([Fe³+][SCN-]) Use the answers for questions 10, 11 and 12 to calculate Kc. Give the answer in two significant figures. azoqquê eau 838.0 ai,benila viriguotori
#71 12. Use your answers for Questions 4 and 10 to calculate [SCN -] q, the equilbrium concentration of SCN-, for the Test Tube 3 reaction mixture described in Question 10. [FeSCN³¹] Initial Change Equilibrium [Fe³] Q1 answer (0.0010) -x (0.0000749) Q11 answer (0.00093) = [SCN -]q, Q4 answer - x 201 [SCN-] Q4 answer (0.00060) -x (0.0000749) Q12 answer (0.00053) +x x=Q10 answer (0.0000749) blano OH to Jm 0.S+ иоx M 900.0 to Jm 13. What is the calculated value of Kc for the Test Tube 3 reaction mixture described in Question 10? To answer this Question, you will need to plug your answers for Questions 10, 11, and 12 into the expression for Kc, which you identified if you correctly answered Question 7. K. = [FeSCN 2+]/([Fe³+][SCN-]) Use the answers for questions 10, 11 and 12 to calculate Kc. Give the answer in two significant figures. azoqquê eau 838.0 ai,benila viriguotori
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Transcription for Educational Website:**
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**Equilibrium Concentration Calculation and Kc Expression**
**12. Use your answers for Questions 4 and 10 to calculate [SCN⁻], the equilibrium concentration of SCN⁻, for the Test Tube 3 reaction mixture described in Question 10.**
| | [Fe³⁺] | [SCN⁻] | [FeSCN²⁺] |
|----------|----------------------------|-----------------------|--------------------------------|
| Initial | Q1 answer (0.0010) | Q4 answer (0.00060) | |
| Change | -x (0.00000749) | -x (0.00000749) | +x |
| Equilibrium | Q11 answer (0.000993) | Q12 answer (0.000553) | x = Q10 answer (0.00000749) |
\[ [\text{SCN}^-]_{\text{eq.}} = \text{Q4 answer} - x \]
**13. What is the calculated value of Kc for the Test Tube 3 reaction mixture described in Question 10? To answer this question, you will need to plug your answers for Questions 10, 11, and 12 into the expression for Kc, which you identified if you correctly answered Question 7.**
Kc = \(\frac{[\text{FeSCN}^{2+}]}{[\text{Fe}^{3+}][\text{SCN}^-]}\)
Use the answers for questions 10, 11, and 12 to calculate Kc. Give the answer in two significant figures.
**Annotations:**
- #10 = 0.00000749
- #11 = 0.000993
- #12 = 0.000553
Use these results to calculate and verify your Kc value.
---](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a31084d-53de-40ac-8333-22b405fb7df5%2F8afbfc39-560e-4ec3-a55d-6921fa87601f%2F4tyb22o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website:**
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**Equilibrium Concentration Calculation and Kc Expression**
**12. Use your answers for Questions 4 and 10 to calculate [SCN⁻], the equilibrium concentration of SCN⁻, for the Test Tube 3 reaction mixture described in Question 10.**
| | [Fe³⁺] | [SCN⁻] | [FeSCN²⁺] |
|----------|----------------------------|-----------------------|--------------------------------|
| Initial | Q1 answer (0.0010) | Q4 answer (0.00060) | |
| Change | -x (0.00000749) | -x (0.00000749) | +x |
| Equilibrium | Q11 answer (0.000993) | Q12 answer (0.000553) | x = Q10 answer (0.00000749) |
\[ [\text{SCN}^-]_{\text{eq.}} = \text{Q4 answer} - x \]
**13. What is the calculated value of Kc for the Test Tube 3 reaction mixture described in Question 10? To answer this question, you will need to plug your answers for Questions 10, 11, and 12 into the expression for Kc, which you identified if you correctly answered Question 7.**
Kc = \(\frac{[\text{FeSCN}^{2+}]}{[\text{Fe}^{3+}][\text{SCN}^-]}\)
Use the answers for questions 10, 11, and 12 to calculate Kc. Give the answer in two significant figures.
**Annotations:**
- #10 = 0.00000749
- #11 = 0.000993
- #12 = 0.000553
Use these results to calculate and verify your Kc value.
---
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