7.S.21 A student recorded the number of calories in each of 56 entrees-28 vegetarian and 28 nonvegetarian-served at acollege dining hall.81 The following table summarizes the data. Graphs of the data (not given here) show that both distributions arereasonably symmetric and bell shaped. A 95% confidence interval for μ₁ - ₂ is (-27, 85). For each of the following, say whetherthe statement is true or false and say why.nMeanSDVegetarian28351119Nonvegetarian2832287a. 95% of the data are between -27 and 85 calories.b. We are 95% confident that μ₁ - 2 is between -27 and 85 calories.c. 95% of the time Y₁ Y2 will be between -27 and 85 calories.d. 95% of the vegetarian entrees have between 27 fewer calories and 85 more calories than the average nonvegetarianentree.

The 95% confidence interval interprets that there is 95% confidence that the difference of the…

Answered: 7.S.21 A student recorded the number of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A 95% confidence interval for the mean (u) of a population is computed from a random sample and found to be 9 ± 3. Which of the following is a correct statement? O a. if we took many, many additional random samples and from each computed a 95% confidence interval for H, approximately 95% of these intervals would contain u. O b. 95% of values sampled are between 6 and 12. O c there is a 95% probability that the true mean is 9 and a 95% chance that the true margin of error is 3. O d. there is a 95% probability that u is between 6 and 12. O e. all of the above are true.
The data in Table represent the population of the statistics students and the marks obtained in the examination on hypothesis tests. Knowing that the previous data are from the population with a normal distributionDetermine:1. Using the T distribution. Make a confidence interval for a 95% confidence level. Alpha mean = .05 enter right value XX.XX Table: 0 0 0 0 0 5 10 15 15 15 20 20 25 25 40 45 50 50 55 75 80 85 90 95 105
2.18 2.42 2.57 2.89 Suppose the data represent the inches of rainfall in April for a certain city over the course of 20 years. 4.79 D 0.53 0.76 1.23 1.37 1.86 3.37 3.66 3.88 4.09 4.49 5.04 5.36 5.79 Given the quartiles Q, = 2.020, Q, = 3.280, and Q3 = 4.640, compute the interquartile range, IQR. 3.19 6.08 IQR =D (Round to three decimal places as needed.)
The following information is obtained for a sample of 80 observations taken from a population. SS xx 370.842, se = 0.922, and y = 164.43 - 2.83x Make a 97 % confidence interval for B. = Round your answers to two decimal places. The 97 % confidence interval for Bis ( i ).
Question 9: compute a 95% confidence interval for the average blood pressure range of any individual that will take the blood pressure medication.
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the table and the g table.) = 30.1, n₁ = 7; 2 = 35.5, n2 = 9; 3 = 40.9, n3 = 4; MSE = 25.0 a. Calculate 95% confidence intervals for H1 H2, H1 - Hз, and μ2 - μз to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round final answers to 2 decimal points.) Population Mean Differences H1-H2 H1 H3 H2 H3 Confidence Interval Can we conclude that the population means differ?
In the following Table are gradients for eight female teeth and eight male teeth. These numbers are measures of the rate of change in the amount of X-ray penetration through a 500-micron section of tooth enamel at a wavelength of 600 nm as opposed to 400 nm. Find the 95% confidence interval for lx - ly. Hint(to.025,14 =2.1448) Male Xi 4.9 5.4 4.8 5.3 5.0 5.5 5.4 6.6 6.3 4.3 Female y; 3.7 4.1 5.6 4.0 3.6 5.0
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5.STATISTICAL INFERENCE
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20.21
Hunter is writing a report on the backgrounds of American presidents. He finds that the mean age of the 45 presidents is 55 years with the standard deviation of 6.59 years. Because Hunter took a statistics course, he calculates a 95% confidence interval for the mean age of all men who have been president to be 55 ± 1.98. Comment on this result. Question 8 options: Hunter can be 95% confident that the mean age of all presidents is 55 years. 95% of all the ages of the presidents lie between 55 ± 1.98. Hunter should have taken a larger sample to reduce the margin of error. Hunter is 95% confident that the mean age of all presidents lies between 53.02 and 56.98 years. The confidence interval makes no sense since Hunter has the entire population of ages.

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