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7-63. The cotter is used to hold the two rods together. Determine the smallest thickness t of the cotter and the smallest diameter d of the rods. All parts are made of steel for which the failure normal stress is fail = 500 MPa and the failure shear stress is fail = 375 MPa. Use a factor of safety of (F.S.), = 2.50 in tension and (F.S.), 1.75 in shear. =

7-63. The cotter is used to hold the two rods together. Determine the smallest thickness t of the cotter and the smallest diameter d of the rods. All parts are made of steel for which the failure normal stress is fail = 500 MPa and the failure shear stress is fail = 375 MPa. Use a factor of safety of (F.S.), = 2.50 in tension and (F.S.), 1.75 in shear. =

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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7-63. The cotter is used to hold the two rods together. Determine the smallest thickness t of the cotter and the smallest diameter d of the rods. All parts are made of steel for which the failure normal stress is fail 500 MPa and the failure shear stress is fail 375 MPa. Use a factor of safety of (F.S.), = 2.50 in tension and (F.S.), = 1.75 in shear. -d- 30 kN 40 mm d - 30 kN t Prob. 7-63 10 mm =
Transcribed Image Text:7-63. The cotter is used to hold the two rods together. Determine the smallest thickness t of the cotter and the smallest diameter d of the rods. All parts are made of steel for which the failure normal stress is fail 500 MPa and the failure shear stress is fail 375 MPa. Use a factor of safety of (F.S.), = 2.50 in tension and (F.S.), = 1.75 in shear. -d- 30 kN 40 mm d - 30 kN t Prob. 7-63 10 mm =
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