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7 1/1 point Find AG at 25°C for: 2 CO (g) + O2(g) · → 2 CO2 (g) Given: 2 CH4(g) +3O2 (g) → 2 CO(g) + 4 H2O(g); CH4(g) +2O2(g) →CO2(g) + 2 H2O(g); AG° = -1088 kJ AG° -801 kJ -275 kJ -884 kJ +425 kJ -514 kJ

7 1/1 point Find AG at 25°C for: 2 CO (g) + O2(g) · → 2 CO2 (g) Given: 2 CH4(g) +3O2 (g) → 2 CO(g) + 4 H2O(g); CH4(g) +2O2(g) →CO2(g) + 2 H2O(g); AG° = -1088 kJ AG° -801 kJ -275 kJ -884 kJ +425 kJ -514 kJ

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.76QE
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7 1/1 point Find AG at 25°C for: 2 CO (g) + O2(g) · → 2 CO2 (g) Given: 2 CH4(g) +3O2 (g) → 2 CO(g) + 4 H2O(g); CH4(g) +2O2(g) →CO2(g) + 2 H2O(g); AG° = -1088 kJ AG° -801 kJ -275 kJ -884 kJ +425 kJ -514 kJ
Transcribed Image Text:7 1/1 point Find AG at 25°C for: 2 CO (g) + O2(g) · → 2 CO2 (g) Given: 2 CH4(g) +3O2 (g) → 2 CO(g) + 4 H2O(g); CH4(g) +2O2(g) →CO2(g) + 2 H2O(g); AG° = -1088 kJ AG° -801 kJ -275 kJ -884 kJ +425 kJ -514 kJ
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