6a. For the cell: Pt(s) | CIO (0.030 M), OH- (0.010 M), CI- (0.015 M) || CI (0.40 M) | Cl₂(g, p the involved electrode processes are: Cl2(g) + 2e2C1¯¯ E° = 1.36 V = 0.25 bar) | Pt(s) ClO3 + 3H2O + 6e → CI¯ + 60H¯ E° = 0.62 V Calculate the electromotive force of the cell. Nernst's equation: 0.0592 V E = E° log Z [red] [ox] 6b. Write down the chemical process that occurs when the cell in question 6a supplies current. 6c. Based on the two electrode processes: S2O + 6H+ + 4e¯¯ → 2S(s) + 3H2O E° = 0.47 V HSO4 + 7H+ + 6e¯¯ → S(s) + 4H₂O_E° = 0.34 V calculate the equilibrium constant for the reaction: 3S2O + 4H = 2HSO4 + 4S(s) + H2O log K ↓ z(E – Eg) 0.0592 V

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 50QRT
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6a. For the cell:
Pt(s) | CIO (0.030 M), OH- (0.010 M), CI- (0.015 M) || CI (0.40 M) | Cl₂(g, p
the involved electrode processes are:
Cl2(g) + 2e2C1¯¯
E°
= 1.36 V
=
0.25 bar) | Pt(s)
ClO3 + 3H2O + 6e → CI¯ + 60H¯ E° = 0.62 V
Calculate the electromotive force of the cell. Nernst's equation:
0.0592 V
E = E°
log
Z
[red]
[ox]
6b. Write down the chemical process that occurs when the cell in question 6a supplies current.
6c. Based on the two electrode processes:
S2O + 6H+ + 4e¯¯ → 2S(s) + 3H2O E° = 0.47 V
HSO4 + 7H+ + 6e¯¯ → S(s) + 4H₂O_E° = 0.34 V
calculate the equilibrium constant for the reaction:
3S2O + 4H = 2HSO4 + 4S(s) + H2O
log K
↓ z(E – Eg)
0.0592 V
Transcribed Image Text:6a. For the cell: Pt(s) | CIO (0.030 M), OH- (0.010 M), CI- (0.015 M) || CI (0.40 M) | Cl₂(g, p the involved electrode processes are: Cl2(g) + 2e2C1¯¯ E° = 1.36 V = 0.25 bar) | Pt(s) ClO3 + 3H2O + 6e → CI¯ + 60H¯ E° = 0.62 V Calculate the electromotive force of the cell. Nernst's equation: 0.0592 V E = E° log Z [red] [ox] 6b. Write down the chemical process that occurs when the cell in question 6a supplies current. 6c. Based on the two electrode processes: S2O + 6H+ + 4e¯¯ → 2S(s) + 3H2O E° = 0.47 V HSO4 + 7H+ + 6e¯¯ → S(s) + 4H₂O_E° = 0.34 V calculate the equilibrium constant for the reaction: 3S2O + 4H = 2HSO4 + 4S(s) + H2O log K ↓ z(E – Eg) 0.0592 V
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