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6. Two reactions will undergo at the same temperature. If Ea2 > Ea1, Please analyze by Arrhenius equation, which reaction would be affected by temperature largely?

6. Two reactions will undergo at the same temperature. If Ea2 > Ea1, Please analyze by Arrhenius equation, which reaction would be affected by temperature largely?

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter15: Equilibria Of Other Reaction Classes
Section: Chapter Questions
Problem 11E: The Handbook of Chemistry and Physics (http://openstaxcollege.org/l/16Handbook) gives solubilities...
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* 6. Please write the answers of 6-8 on one paper, and submit the photo. 6. Two reactions will undergo at the same temperature. If Ea2 > Ea1, Please analyze by Arrhenius equation, which reaction would be affected by temperature largely? 7. Explain the reason why the solubility of BaS04(s) in saline is greater than that in pure water, while the solubility of AgCl(s) in saline is lower than in pure water.- 8. Calculate the molliosmolarity (mOsM) of 0.9% NacI (MM. = 58.5g/mol) saline solution and 5% glucose (MM. = 180g/mol) solution at normal body temperature (37°C). Note that the density of them is 1.00 g-mL¯1. %3D %3D
Transcribed Image Text:* 6. Please write the answers of 6-8 on one paper, and submit the photo. 6. Two reactions will undergo at the same temperature. If Ea2 > Ea1, Please analyze by Arrhenius equation, which reaction would be affected by temperature largely? 7. Explain the reason why the solubility of BaS04(s) in saline is greater than that in pure water, while the solubility of AgCl(s) in saline is lower than in pure water.- 8. Calculate the molliosmolarity (mOsM) of 0.9% NacI (MM. = 58.5g/mol) saline solution and 5% glucose (MM. = 180g/mol) solution at normal body temperature (37°C). Note that the density of them is 1.00 g-mL¯1. %3D %3D
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