6. Determine the structures of the following aromatic compounds based on their NMR spectra.Copyright McGraw-Hill Education. All rights reserved. No reproduction ordistribution without the prior written consent of McGraw-Hill Education.a. C,0H14: IR absorptions at 3150-2850, 1600, and 1500 cmb. CoH12: C NMR signals at 21, 127, and 138 ppmH NMR spectrum6 HH NMR spectrum9 H3 H1 H3 H4 H8.6.5.426.4ppmppmc. C3H10: IR absorptions at 3108-2875, 1606, and 1496 cmH NMR spectrum3 H5 H2H0.8.7.6.4.3ppmGIAYFocus2.3.2.CO

Question 6 (c) Answer: In the given information, the IR stretching frequency is due to the bond…

Answered: c. CBH10: IR absorptions at 3108-2875,…

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c. CBH10: IR absorptions at 3108-2875, 1606, and 1496 cm 1H NMR spectrum 3 H 5 H 2H 7. 6. 5 3. ppm

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

6. Determine the structures of the following aromatic compounds based on their NMR spectra.
Copyright McGraw-Hill Education. All rights reserved. No reproduction or
distribution without the prior written consent of McGraw-Hill Education.
a. C,0H14: IR absorptions at 3150-2850, 1600, and 1500 cm
b. CoH12: C NMR signals at 21, 127, and 138 ppm
H NMR spectrum
6 H
H NMR spectrum
9 H
3 H
1 H
3 H
4 H
8.
6.
5.
4
2
6.
4
ppm
ppm
c. C3H10: IR absorptions at 3108-2875, 1606, and 1496 cm
H NMR spectrum
3 H
5 H
2H
0.
8.
7.
6.
4.
3
ppm
GIAY
Focus
2.
3.
2.
CO

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