**Problem:**A 100 kg scaffold is 6.60 m long. It is hanging with two wires, one from each end. A 440 kg box sits 1.50 m from the left end. What is the tension in the left-hand side wire? (Assume \( g = 9.8 \, \text{m/s}^2 \))**Solution:**To find the tension in the left-hand side wire, we need to consider the forces acting on the scaffold. The total force on the system is due to the weight of the scaffold and the box. The scaffold can be modeled as a uniform beam, and the effects of the box need to be considered to the left of the beam. The weights and distances will be used to calculate the torque about the right-hand side wire.- **Weight of the scaffold (W_s):** \[ W_s = m_s \times g = 100 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 980 \, \text{N} \] - **Weight of the box (W_b):** \[ W_b = m_b \times g = 440 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 4312 \, \text{N} \] The sum of the torques around the right wire will be zero, as the scaffold is in equilibrium.Using these equations, you can calculate the tension in the left wire by solving the equilibrium of torques and forces. The math and physics involved provide insight into static equilibrium in mechanics.

The mass of the scaffold is m = 100 kg. The mass of the box is mB = 440 kg. The length of the…

6. A 100 kg scaffold is 6.60 m long. It is hanging with two wires, one from each end. A 440 kg box sits 1.50 m from the left end. What is the tension in the left hand side wire?(g = 9.8 m/s²) Newtons

6. A 100 kg scaffold is 6.60 m long. It is hanging with two wires, one from each end. A 440 kg box sits 1.50 m from the left end. What is the tension in the left hand side wire?(g = 9.8 m/s²) Newtons

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

Question

**Problem:**

A 100 kg scaffold is 6.60 m long. It is hanging with two wires, one from each end. A 440 kg box sits 1.50 m from the left end. What is the tension in the left-hand side wire? (Assume \( g = 9.8 \, \text{m/s}^2 \))

**Solution:**

To find the tension in the left-hand side wire, we need to consider the forces acting on the scaffold. The total force on the system is due to the weight of the scaffold and the box.

The scaffold can be modeled as a uniform beam, and the effects of the box need to be considered to the left of the beam. The weights and distances will be used to calculate the torque about the right-hand side wire.

- **Weight of the scaffold (W_s):**
\[
W_s = m_s \times g = 100 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 980 \, \text{N}
\]

- **Weight of the box (W_b):**
\[
W_b = m_b \times g = 440 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 4312 \, \text{N}
\]

The sum of the torques around the right wire will be zero, as the scaffold is in equilibrium.

Using these equations, you can calculate the tension in the left wire by solving the equilibrium of torques and forces. The
math and physics involved provide insight into static equilibrium in mechanics.

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