**Educational Exercise: Calculating Mass with Friction****Problem Statement:**A man is supporting his weight through friction while pressing into rock walls with his feet and back. Assume friction is completely supporting his weight – he might use the rope for balance without pulling. The normal force on his feet (combined from both feet and back) is 743.2 N. Given a coefficient of static friction of 0.54, calculate his mass if he is just barely not slipping.**Question:**What is the man's mass?- **Normal Force:** 743.2 N- **Coefficient of Static Friction:** 0.54**Diagram:**The image shows a man in a climbing position, using friction against rock walls to maintain his stance.**Calculation:**We use the equation for friction: \[ f = \mu \cdot N \] where \( f \) is the frictional force, \( \mu \) is the coefficient of static friction, and \( N \) is the normal force.To find the man's mass (\( m \)), use the balance between gravitational force and frictional force:\[ m \cdot g = \mu \cdot N \]Solving for \( m \):\[ m = \frac{\mu \cdot N}{g} \]where \( g \approx 9.81 \, \text{m/s}^2 \) (acceleration due to gravity).**Calculation Attempt:**An initial calculation of 40.95 kg was attempted but deemed incorrect. Ensure correct substitution and calculation for accuracy.**Previous Submissions:**- 40.95 kg (incorrect)**Answer Input Box:**- [Mass: _____ kg] [Incorrect]### Conclusion:Perform the calculation carefully, checking each step to find the correct mass that satisfies the given conditions.

The upward friction force is μN on both feet and back. This force must equal the weight of person.…

The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass?

The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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