The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass? A
The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass? A
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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
Transcribed Image Text:**Educational Content: Friction and Force Analysis**
**Problem Statement:**
A man is supporting his weight using friction by pressing into rock walls with his feet and back. Assume that friction is counteracting all his weight, with the possibility that he is only using a rope for stabilization, not support. The normal force exerted on his feet (with both feet combined) and his back is 743.2 N. Given the coefficient of static friction as 0.54, if the man is just barely not slipping down, what is his mass?
**Diagram Description:**
The image depicts a climber positioned between two vertical rock walls. The climber is shown pressing against the walls with his feet and back for support, holding a rope which is presumably not providing additional upward force.
**Additional Information:**
The user is prompted to enter the mass in kilograms.
**Previous Submissions:**
- 40.95 kg
The problem involves calculating the climber's mass using principles of physics, particularly the static friction equation.
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