**Physics Problem: Normal Force on an Inclined Plane**A block of mass \(m\) sits at rest on a rough inclined ramp that makes an angle \(\theta\) with the horizontal. What must be true about the normal force \(F\) on the block due to the ramp?**Options:**- **A.** \( F = mg \cos\theta \)- **B.** \( F > mg \)- **C.** \( F > mg \sin\theta \)- **D.** \( F > mg \cos\theta \)- **E.** \( F = mg \sin\theta \)*Explanation:*When a block is resting on an inclined plane, there are several forces acting on it:1. The gravitational force (\(mg\)) acts vertically downward.2. The normal force (\(F\)) acts perpendicular to the surface of the incline.3. The frictional force (if any) acts parallel to the surface of the incline, opposing the motion or potential motion of the block.To find the normal force (\(F\)), we need to consider the components of the gravitational force:- The component of the gravitational force perpendicular to the incline is \(mg \cos\theta\).- The component of the gravitational force parallel to the incline is \(mg \sin\theta\).For a block at rest on a rough incline, the normal force \(F\) is equal to the perpendicular component of the gravitational force:\[ F = mg \cos\theta \]Therefore, the correct option is:**A. \( F = mg \cos\theta \)**

Name: **Physics Problem: Normal Force on an Inclined Plane**A block of mass
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: **Physics Problem: Normal Force on an Inclined Plane**A block of mass \(m\) sits at rest on a rough inclined ramp that makes an angle \(\theta\) with the horizontal. What must be true about the normal force \(F\) on the block due to the ramp?**Optio