6- what does happen if a 2 MW load with the power factor of 0.7 is added to the firstbus as follow? What is the voltage drop at this state?a63 KV / 20 KV0.4+10,3 Ω2 MWCosp = 0.70.3+j0.2 2Load1:3 MWCosp = 10.5+j0.4 2Load2:I MWCosqp=1Load3:2 MWCosp = 0.8

Given data Source voltage, 66 KV/20 KV Bus-1, 2 MW, cosφ=0.7 Load1: 3 MW, cosφ=1 Load2: 1 MW, cosφ=1…

6- what does happen if a 2 MW load with the power factor of 0.7 is added to the first bus as follow? What is the voltage drop at this state? œ 63 KV/20 KV 0.4+j0.3 2 2 MW Cosp=0.7 0.3+j0.22 Load1: 3 MW Coso = 1 0.5+j0.492 Load2: I MW Coso = 1 Load3: 2 MW Cosp=0.8

6- what does happen if a 2 MW load with the power factor of 0.7 is added to the first bus as follow? What is the voltage drop at this state? œ 63 KV/20 KV 0.4+j0.3 2 2 MW Cosp=0.7 0.3+j0.22 Load1: 3 MW Coso = 1 0.5+j0.492 Load2: I MW Coso = 1 Load3: 2 MW Cosp=0.8

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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The conversion of electrical energy to heat energy is known as electric heating. The heating system that converts the electrical energy to heat energy for various application is called electrical heating unit. Electricity is employed as the firing mechanism in electric heating systems, which transforms electric current to heat. Electric heaters have heating elements in the form of electric resistors.

Question

6- what does happen if a 2 MW load with the power factor of 0.7 is added to the first
bus as follow? What is the voltage drop at this state?
a
63 KV / 20 KV
0.4+10,3 Ω
2 MW
Cosp = 0.7
0.3+j0.2 2
Load1:
3 MW
Cosp = 1
0.5+j0.4 2
Load2:
I MW
Cosqp=1
Load3:
2 MW
Cosp = 0.8

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6- what does happen if a 2 MW load with the power factor of 0.7 is added to the first bus as follow? What is the voltage drop at this state? a 63 KV / 20 KV 0.4+10.3 Ω 2 MW Cosp = 0.7 0.3+j0.2 2 Load1: 3 MW Cosp = 1 0.5+j0.4 Ω Load2: 1 MW Cosp = 1 Load3: 2 MW Cosp = 0.8
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