6) The following set of data was obtained by the method of initial rates for the reaction: 2 HgCl2(aq) + C2O42-(aq) - 2 Cl-(aq) + 2 CO2(g) + Hg2Cl2(s) What is the rate law for the reaction? [HgCl2], M [C2O42-1, M | Rate, M/s 0.10 0.10 1.3 x 10-7 0.10 0.20 5.2 x 10-7 0.20 0.20 1.0 x 10-6 A) Rate = k[HgCl2][C2O42-]-2 C) Rate = k[HgCl2]²[C2O42-] B) Rate = k[HgCl2][C2O42-]-1 D) Rate = k[HgCl2][C2042-12
6) The following set of data was obtained by the method of initial rates for the reaction: 2 HgCl2(aq) + C2O42-(aq) - 2 Cl-(aq) + 2 CO2(g) + Hg2Cl2(s) What is the rate law for the reaction? [HgCl2], M [C2O42-1, M | Rate, M/s 0.10 0.10 1.3 x 10-7 0.10 0.20 5.2 x 10-7 0.20 0.20 1.0 x 10-6 A) Rate = k[HgCl2][C2O42-]-2 C) Rate = k[HgCl2]²[C2O42-] B) Rate = k[HgCl2][C2O42-]-1 D) Rate = k[HgCl2][C2042-12
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![6) The following set of data was obtained by the method of initial rates for the reaction:
2 HgCl2(aq) + C2042-(aq) - 2 Cl-(ag) + 2 CO2(g) + Hg2C12(s)
What is the rate law for the reaction?
[HgCl2], M [C2042-1, M | Rate, M/s
0.10
0.10
1.3 x 10-7
0.10
0.20
5.2 x 10-7
0.20
0.20
1.0 x 10-6
A) Rate = k[HgCl2][C2O42-]-2
- k[HgCl2]?[C2O42-]
B) Rate = k[HgCl2][C2O42-]-1
D) Rate = k[HgCl2][C2042-12
C) Rate =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7fa36a0f-8029-4102-9463-96b546e66a8d%2Fc6db6f8d-ed64-491a-b106-996263227705%2F1m27jk_processed.png&w=3840&q=75)
Transcribed Image Text:6) The following set of data was obtained by the method of initial rates for the reaction:
2 HgCl2(aq) + C2042-(aq) - 2 Cl-(ag) + 2 CO2(g) + Hg2C12(s)
What is the rate law for the reaction?
[HgCl2], M [C2042-1, M | Rate, M/s
0.10
0.10
1.3 x 10-7
0.10
0.20
5.2 x 10-7
0.20
0.20
1.0 x 10-6
A) Rate = k[HgCl2][C2O42-]-2
- k[HgCl2]?[C2O42-]
B) Rate = k[HgCl2][C2O42-]-1
D) Rate = k[HgCl2][C2042-12
C) Rate =
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