6-20. A 4.476-g sample of a petroleum product was burned in a tube furnace, and the SO, produced was col- lected in 3% H,O2. Reaction: SO,(g) + H,O, →H,SO4 A 25.00-mL portion of 0.00923 M NaOH was intro- duced into the solution of H,SO,, following which the excess base was back-titrated with 13.33 mL of 0.01007 M HCI. Calculate the parts per million of sulfur in the sample.
6-20. A 4.476-g sample of a petroleum product was burned in a tube furnace, and the SO, produced was col- lected in 3% H,O2. Reaction: SO,(g) + H,O, →H,SO4 A 25.00-mL portion of 0.00923 M NaOH was intro- duced into the solution of H,SO,, following which the excess base was back-titrated with 13.33 mL of 0.01007 M HCI. Calculate the parts per million of sulfur in the sample.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:6-20. A 4.476-g sample of a petroleum product was burned
in a tube furnace, and the SO, produced was col-
lected in 3% H,O2. Reaction:
SO-(g) + H;O, → H,SO4
A 25.00-mL portion of 0.00923 M NaOH was intro-
duced into the solution of H,SO,, following which
the excess base was back-titrated with 13.33 mL of
0.01007 M HCI. Calculate the parts per million of
sulfur in the sample.
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