5.11(a) Develop an electron-equivalent fermentation energy-reaction for conversion ofpropionate into 1 mol acetate and the remainder of the electrons into H,.(b) Calculate AG for the reaction assuming pH 7.0 and standard conditions of 1 mol/1for acetate and propionate and 1 atm partial pressure for H,.(c) Calculate AG, for the reaction assuming pH 7.0 and 500 mg/l propionate, 50 mg/lacetate, and 10-5 atm partial pressure for H,.(d) Discuss under which of the conditions found from parts (b) and (c) that biologicalgrowth might occur and why.

Since you have asked multiple questions questions, we will solve the first question for you. If you…

5.11 (a) Develop an electron-equivalent fermentation energy-reaction for conversion of propionate into 1 mol acetate and the remainder of the electrons into H,. (b) Calculate AG for the reaction assuming pH 7.0 and standard conditions of 1 nmol/1

5.11 (a) Develop an electron-equivalent fermentation energy-reaction for conversion of propionate into 1 mol acetate and the remainder of the electrons into H,. (b) Calculate AG for the reaction assuming pH 7.0 and standard conditions of 1 nmol/1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

5.11
(a) Develop an electron-equivalent fermentation energy-reaction for conversion of
propionate into 1 mol acetate and the remainder of the electrons into H,.
(b) Calculate AG for the reaction assuming pH 7.0 and standard conditions of 1 mol/1
for acetate and propionate and 1 atm partial pressure for H,.
(c) Calculate AG, for the reaction assuming pH 7.0 and 500 mg/l propionate, 50 mg/l
acetate, and 10-5 atm partial pressure for H,.
(d) Discuss under which of the conditions found from parts (b) and (c) that biological
growth might occur and why.

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