5. Suppose JP performs the hypothesis test Ho: µ = 70 versus H1: µ # 70. We find a 96%confidence interval for u to be 65.4 < u < 68.9. We draw the conclusion that we Do NotReject Ho at a 4% significance level. Was our conclusion correct? Explain your answer.

Given , Hypothesis : H0 : μ = 70 H1 : μ ≠ 70 A 96% confidence interval for population mean (μ) is…

Answered: 5. Suppose JP performs the hypothesis…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose 250 subjects are treated with a drug that is used to treat pain and 50 of them developed nausea. Use a 0.05 significance level to test the claim that more than 20% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. OA. Ho: p=0.20 H₁: p=0.20 OB. Ho: p=0.20 H₁: p0.20 H₁: p=0.20 D. Ho: p=0.20 H₁: p>0.20 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) hco
19. A consumer.research firm reports that the 95% confidence interval for the proportion of consumers who prefer brand K tissue is 0.38 ± 0.04. If the research firm also conducts a significance test of the null hypothesis Ho:p = Po against the alternative Ha:p# Po, which of the following statements must be %3D true? (A) If po = 0.35, then the null hypothesis will be rejected at the a = 0.05 significance level. (B) If po = 0.35, then the null hypothesis will be rejected at the a = 0.01 significance level. %3D (C) If po = 0.38, then the null hypothesis will be rejected at the a = 0.05 significance level. (D) If Po = 0.38, then the null hypothesis will be rejected at the a= 0.01 significance level. (E) If Po = 0.43, then the null hypothesis will be rejected at the a= 0.05 significance level.
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Use the following ANOVA table for regression to answer the questions. Analysis of Variance Source DF SS MS F P Regression 3377.5 3377.5 18.1 0.000 Residual Error 174 32468.4 186.6 Total 175 35845.9 Give the F-statistic and p-value. Enter the exact answers. The F-statistic is i The p-value is i eTextbook and Media Hint 63°F Cla Type here to search
The recidivism rate for convicted sex offenders is 11%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 337 convicted sex offenders who were also drug addicts, 30 of them became repeat offenders. What can be concluded at the a = 0.10 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: Ho: ? ✓ Select an answer H₁: ? ✓ Select an answer (please enter a decimal) (Please enter a decimal) The test statistic ? ✓ = The p-value = The p-value is? ♥ α Based on this, we should [Select an answer the null hypothesis. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the population proportion is not significantly different from 11% at a = 0.10, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become…
A change is made that should improve student satisfaction with the parking situation at your school. Before the change, 37% of students approve of the parking that's provided. The null hypothesis Ho : p = 0.37 is tested against the alternative H.: p > 0.37 The given hypotheses are incorrect. What are the appropriate hypotheses for performing this significance test? Ho : p = 0.37; Ha :p> 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p = 0.37; Ho : p + 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p > 0.37; Họ : p = 0.37, where p= the true proportion of students that approve of the parking that's provided. Ho : p = 0.37; H, : p + 0.37, where p the sample proportion of students that approve of the parking that's provided. Ho : p > 0.37; Họ : p = 0.37, where p the sample proportion of students that approve of the parking that's provided.
Suppose a 95% confidence interval for the difference in test scores between Class 1 and Class 2 (in that order) is the following: 9 +/− 2. These results were based on independent samples of size 100 from each class. Now suppose you switch the order of Class 1 and Class 2 in your analysis but keep the data labeled correctly in terms of which class they came from. Which of the following statements is false? A) You can't do it this way. You'll get negative numbers for the difference in the means and/or negative numbers for the standard error. B) You are confident that the average for Class 2 is 7 to 11 points lower than for Class 1. C) You are still confident that the classes have significantly different mean scores. D) Your 95% confidence interval will now be entirely negative: from −7 to −11.
Suppose you are planning an experiment and a sample has yet been selected. For this experiment you plan on taking a SRS of 50 mice with pancreatic cancer measuring a particular hormone level. What would be the impact on a 95% confidence interval calculated from the experiment on these mice if instead of a SRS of 50 mice, a SRS of 200 mice were taken?
Prof. Johnson conducts a hypothesis test on whether the proportion of all UBC students who bike to school (denoted as p) equals 30%. Specifically, Prof.Johnson has H0:p=0.3 versus HA:p≠0.3. He obtains a P-value of 0.01. On the other hand, Prof. Smith would like to test if there is sufficient evidence to support that p is greater than 0.3 at the 10% significance level. Based on Prof. Johnson's result, will the null hypothesis of Prof. Smith's test be rejected? A. There is insufficient information to tell.B. Yes.C. No.
Previously, 10.4% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 75 workers and finds that 16 of them have a travel time to work that is more than 60 minutes. Test the economist's belief at the a = 0.1 level of significance. What are the null and alternative hypotheses? 0.104 versus H1: p Ho: p P = (Type integers or decimals. Do not round.) > 0.104 %3D Because npo (1- Po) 10, the normal model be used to approximate the P-value. %3D (Round to one decimal place as needed.)
Imagine that you found that participants in the jelly bean condition had an average acne score o and your significance level was .041. Because your signifinace level is lEss than .05 you reject the null hypothesis. Result #2 imagine that you found that the participants in the jelly bean condition had an average acne score of and your significance level was .00. Because your significance level is less than .05 you reject the null hypothesis. You also note that this result suggest a bigger effect size(30verus10 on your dependant variable). What is the ma in difference between the two scenarios?
Next Question Assume a significance level of a = 0.05 and use the given information to cd d (b) below. Original claim: More than 43% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.0443. ..... a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. A. Fail to reject Ho because the P-value is greater than x. B. Reject H, because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Reject Ho because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 43%. B. There is not sufficient evidence to support the…

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5. Suppose JP performs the hypothesis test Ho: u = 70 versus H1: u 70. We find a 96% confidence interval for u to be 65.4 < u < 68.9. We draw the conclusion that we Do Not Reject Ho at a 4% significance level. Was our conclusion correct? Explain your answer.