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5. For the following compound rank the proton groups from most reactive to the least reactive in free radical bromination. CH₂ H₂C H₂C CH₂ CH CH3

5. For the following compound rank the proton groups from most reactive to the least reactive in free radical bromination. CH₂ H₂C H₂C CH₂ CH CH3

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question 5:** For the following compound, rank the proton groups from most reactive to least reactive in free radical bromination. **Diagram Analysis:** The diagram is a chemical structure featuring a benzene ring attached to an isopropyl group (CH(CH3)2) on one side and a propane group (CH2CH3) on another. The molecule is 1-isopropyl-4-ethylbenzene. **Explanation of Diagram:** - The benzene ring is a hexagonal structure with alternating double bonds, representing delocalized pi-electrons. - The isopropyl group consists of a central carbon atom bonded to one hydrogen atom and two methyl groups (CH3). - The ethyl group is composed of a two-carbon chain bonded to the benzene ring. **Context for Educational Website:** In the context of free radical bromination, primary, secondary, and tertiary hydrogen atoms exhibit different reactivities. Generally, tertiary hydrogens are most reactive, followed by secondary, and then primary. The benzylic position (adjacent to the aromatic ring) also influences reactivity due to stabilization by the aromatic system. **Instruction:** When ranking the proton groups based on their reactivity toward bromination, consider factors such as stability of the resulting radical, the number of substituents, and proximity to the benzene ring.
Transcribed Image Text:**Question 5:** For the following compound, rank the proton groups from most reactive to least reactive in free radical bromination. **Diagram Analysis:** The diagram is a chemical structure featuring a benzene ring attached to an isopropyl group (CH(CH3)2) on one side and a propane group (CH2CH3) on another. The molecule is 1-isopropyl-4-ethylbenzene. **Explanation of Diagram:** - The benzene ring is a hexagonal structure with alternating double bonds, representing delocalized pi-electrons. - The isopropyl group consists of a central carbon atom bonded to one hydrogen atom and two methyl groups (CH3). - The ethyl group is composed of a two-carbon chain bonded to the benzene ring. **Context for Educational Website:** In the context of free radical bromination, primary, secondary, and tertiary hydrogen atoms exhibit different reactivities. Generally, tertiary hydrogens are most reactive, followed by secondary, and then primary. The benzylic position (adjacent to the aromatic ring) also influences reactivity due to stabilization by the aromatic system. **Instruction:** When ranking the proton groups based on their reactivity toward bromination, consider factors such as stability of the resulting radical, the number of substituents, and proximity to the benzene ring.
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