(5.) Evaluate the path integral C F(1) = <-, \n (2), 1>5 F(0) = < 0, 0, Fd, where F = (y sin(z), x sin(z), xy cos()) and C is the path that πt. follows the parametric curve ☞(t) = (te' cos(πt), In(t + 1), sin² (7/7)) 0 ≤ t≤1 2 FXF = ^ k (1sin(2) x (2) xg cos(2) = g (4,2) = g(z) ×૧૮૮૨) - f(x, y, z) = xy sin (2) +C

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
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Please review and solve the following problem. The screenshot listed already has some work done and the correct answer listed. Please solve the problem and include an explanation of how the work was solved. Also, Please make sure to double check the answer provided matches up with the screenshot and the work is properly formatted so I am able to follow along. Thanks :)

(5.) Evaluate the path integral
C
F(1) = <-, \n (2), 1>5
F(0) = < 0, 0,
Fd, where F = (y sin(z), x sin(z), xy cos()) and C is the path that
πt.
follows the parametric curve ☞(t) = (te' cos(πt), In(t + 1), sin² (7/7)) 0 ≤ t≤1
2
FXF =
^
k
(1sin(2) x (2)
xg cos(2)
=
<XCUS(Z)-XC07(Z),
of (F($)) - f (*(os)
YCOS(2)). YLOD(2),
sii (2)-siulz)) = ö
=
1-14(2). Sin (1)
0
-eln (2) sin (1)
= f(x,y,2) = fysin (2) dx +9cy,z)
=)
xys(z) + g(y, z)
by = xsin (2) +gy (4,2) = xsin (2)
f = xy sn (2) +9(2)
b₂ = xy cos(z) + g'(z)
-
» g'(2)=0
=>
g (4,2) = g(z)
×૧૮૮૨)
-
f(x, y, z) = xy sin (2) +C
Transcribed Image Text:(5.) Evaluate the path integral C F(1) = <-, \n (2), 1>5 F(0) = < 0, 0, Fd, where F = (y sin(z), x sin(z), xy cos()) and C is the path that πt. follows the parametric curve ☞(t) = (te' cos(πt), In(t + 1), sin² (7/7)) 0 ≤ t≤1 2 FXF = ^ k (1sin(2) x (2) xg cos(2) = <XCUS(Z)-XC07(Z), of (F($)) - f (*(os) YCOS(2)). YLOD(2), sii (2)-siulz)) = ö = 1-14(2). Sin (1) 0 -eln (2) sin (1) = f(x,y,2) = fysin (2) dx +9cy,z) =) xys(z) + g(y, z) by = xsin (2) +gy (4,2) = xsin (2) f = xy sn (2) +9(2) b₂ = xy cos(z) + g'(z) - » g'(2)=0 => g (4,2) = g(z) ×૧૮૮૨) - f(x, y, z) = xy sin (2) +C
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