8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither. lim x-x√x x+2x+3x-5 Solution 1 lim x-x√x *-* 2x3/2+3x-5 = lim x-x√x x+2x-√x+3x-5 -1 Solution 2 lim x-x√x x+2x3/2+3x-5 (0, 0.5, 1) for dividing top and bottom by x√x. = lim 2+示 lim +-1 2+3 lim-5. lim. lim x+00 (0, 0.5, 1) for intermediate algebra and limit laws 0-1 2+3(0)-5(0)(0) 2 (0, 0.5, 1) for final answer. - lim 3/2 (x-1/2-1) x³/2 (2+3x-1/2-5x-³/2) x +x = lim +-1 x→ 2+ 亦 √x lim +-1 2+3.lim -5.lim 4- lim 0-1 2+3(0)-5(0)(0) 2 -1 (0, 0.5, 1) for extracting Cancelling the common factor from the top and the bottom (0, 0.5, 1) for intermediate algebra and limit laws (0, 0.5, 1) for final answer.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 51E
Question

Can you show the steps of how to get this answer, and explain all the steps. You can pick any of the 2 solutions.

8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither.
lim
x-x√x
x+2x+3x-5
Solution 1
lim
x-x√x
*-* 2x3/2+3x-5
=
lim
x-x√x
x+2x-√x+3x-5
-1
Solution 2
lim
x-x√x
x+2x3/2+3x-5
(0, 0.5, 1) for dividing
top and bottom by
x√x.
= lim
2+示
lim +-1
2+3 lim-5. lim. lim
x+00
(0, 0.5, 1) for
intermediate algebra
and limit laws
0-1
2+3(0)-5(0)(0)
2
(0, 0.5, 1) for final
answer.
- lim
3/2 (x-1/2-1)
x³/2 (2+3x-1/2-5x-³/2)
x +x
= lim
+-1
x→ 2+ 亦
√x
lim +-1
2+3.lim -5.lim 4- lim
0-1
2+3(0)-5(0)(0) 2
-1
(0, 0.5, 1) for extracting
Cancelling the common
factor
from the top
and the bottom
(0, 0.5, 1) for
intermediate algebra
and limit laws
(0, 0.5, 1) for final
answer.
Transcribed Image Text:8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither. lim x-x√x x+2x+3x-5 Solution 1 lim x-x√x *-* 2x3/2+3x-5 = lim x-x√x x+2x-√x+3x-5 -1 Solution 2 lim x-x√x x+2x3/2+3x-5 (0, 0.5, 1) for dividing top and bottom by x√x. = lim 2+示 lim +-1 2+3 lim-5. lim. lim x+00 (0, 0.5, 1) for intermediate algebra and limit laws 0-1 2+3(0)-5(0)(0) 2 (0, 0.5, 1) for final answer. - lim 3/2 (x-1/2-1) x³/2 (2+3x-1/2-5x-³/2) x +x = lim +-1 x→ 2+ 亦 √x lim +-1 2+3.lim -5.lim 4- lim 0-1 2+3(0)-5(0)(0) 2 -1 (0, 0.5, 1) for extracting Cancelling the common factor from the top and the bottom (0, 0.5, 1) for intermediate algebra and limit laws (0, 0.5, 1) for final answer.
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