8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither. lim x-x√x x+2x+3x-5 Solution 1 lim x-x√x *-* 2x3/2+3x-5 = lim x-x√x x+2x-√x+3x-5 -1 Solution 2 lim x-x√x x+2x3/2+3x-5 (0, 0.5, 1) for dividing top and bottom by x√x. = lim 2+示 lim +-1 2+3 lim-5. lim. lim x+00 (0, 0.5, 1) for intermediate algebra and limit laws 0-1 2+3(0)-5(0)(0) 2 (0, 0.5, 1) for final answer. - lim 3/2 (x-1/2-1) x³/2 (2+3x-1/2-5x-³/2) x +x = lim +-1 x→ 2+ 亦 √x lim +-1 2+3.lim -5.lim 4- lim 0-1 2+3(0)-5(0)(0) 2 -1 (0, 0.5, 1) for extracting Cancelling the common factor from the top and the bottom (0, 0.5, 1) for intermediate algebra and limit laws (0, 0.5, 1) for final answer.

8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither. lim x-x√x x+2x+3x-5 Solution 1 lim x-x√x - 2x3/2+3x-5 = lim x-x√x x+2x-√x+3x-5 -1 Solution 2 lim x-x√x x+2x3/2+3x-5 (0, 0.5, 1) for dividing top and bottom by x√x. = lim 2+示 lim +-1 2+3 lim-5. lim. lim x+00 (0, 0.5, 1) for intermediate algebra and limit laws 0-1 2+3(0)-5(0)(0) 2 (0, 0.5, 1) for final answer. - lim 3/2 (x-1/2-1) x³/2 (2+3x-1/2-5x-³/2) x +x = lim +-1 x→ 2+ 亦 √x lim +-1 2+3.lim -5.lim 4- lim 0-1 2+3(0)-5(0)(0) 2 -1 (0, 0.5, 1) for extracting Cancelling the common factor from the top and the bottom (0, 0.5, 1) for intermediate algebra and limit laws (0, 0.5, 1) for final answer.

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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