8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither. lim x-x√x x+2x+3x-5 Solution 1 lim x-x√x *-* 2x3/2+3x-5 = lim x-x√x x+2x-√x+3x-5 -1 Solution 2 lim x-x√x x+2x3/2+3x-5 (0, 0.5, 1) for dividing top and bottom by x√x. = lim 2+示 lim +-1 2+3 lim-5. lim. lim x+00 (0, 0.5, 1) for intermediate algebra and limit laws 0-1 2+3(0)-5(0)(0) 2 (0, 0.5, 1) for final answer. - lim 3/2 (x-1/2-1) x³/2 (2+3x-1/2-5x-³/2) x +x = lim +-1 x→ 2+ 亦 √x lim +-1 2+3.lim -5.lim 4- lim 0-1 2+3(0)-5(0)(0) 2 -1 (0, 0.5, 1) for extracting Cancelling the common factor from the top and the bottom (0, 0.5, 1) for intermediate algebra and limit laws (0, 0.5, 1) for final answer.
8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither. lim x-x√x x+2x+3x-5 Solution 1 lim x-x√x *-* 2x3/2+3x-5 = lim x-x√x x+2x-√x+3x-5 -1 Solution 2 lim x-x√x x+2x3/2+3x-5 (0, 0.5, 1) for dividing top and bottom by x√x. = lim 2+示 lim +-1 2+3 lim-5. lim. lim x+00 (0, 0.5, 1) for intermediate algebra and limit laws 0-1 2+3(0)-5(0)(0) 2 (0, 0.5, 1) for final answer. - lim 3/2 (x-1/2-1) x³/2 (2+3x-1/2-5x-³/2) x +x = lim +-1 x→ 2+ 亦 √x lim +-1 2+3.lim -5.lim 4- lim 0-1 2+3(0)-5(0)(0) 2 -1 (0, 0.5, 1) for extracting Cancelling the common factor from the top and the bottom (0, 0.5, 1) for intermediate algebra and limit laws (0, 0.5, 1) for final answer.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 51E
Question
Can you show the steps of how to get this answer, and explain all the steps. You can pick any of the 2 solutions.
![8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither.
lim
x-x√x
x+2x+3x-5
Solution 1
lim
x-x√x
*-* 2x3/2+3x-5
=
lim
x-x√x
x+2x-√x+3x-5
-1
Solution 2
lim
x-x√x
x+2x3/2+3x-5
(0, 0.5, 1) for dividing
top and bottom by
x√x.
= lim
2+示
lim +-1
2+3 lim-5. lim. lim
x+00
(0, 0.5, 1) for
intermediate algebra
and limit laws
0-1
2+3(0)-5(0)(0)
2
(0, 0.5, 1) for final
answer.
- lim
3/2 (x-1/2-1)
x³/2 (2+3x-1/2-5x-³/2)
x +x
= lim
+-1
x→ 2+ 亦
√x
lim +-1
2+3.lim -5.lim 4- lim
0-1
2+3(0)-5(0)(0) 2
-1
(0, 0.5, 1) for extracting
Cancelling the common
factor
from the top
and the bottom
(0, 0.5, 1) for
intermediate algebra
and limit laws
(0, 0.5, 1) for final
answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6356ceb6-8738-457b-86a1-1decb02218d2%2F6f5c2a72-31a8-4fad-b82c-766acc6e8957%2Fnjyujqk_processed.png&w=3840&q=75)
Transcribed Image Text:8. (3 pts) Evaluate the limit if it exists. If it does not exist, explain whether it is co, -co, or neither.
lim
x-x√x
x+2x+3x-5
Solution 1
lim
x-x√x
*-* 2x3/2+3x-5
=
lim
x-x√x
x+2x-√x+3x-5
-1
Solution 2
lim
x-x√x
x+2x3/2+3x-5
(0, 0.5, 1) for dividing
top and bottom by
x√x.
= lim
2+示
lim +-1
2+3 lim-5. lim. lim
x+00
(0, 0.5, 1) for
intermediate algebra
and limit laws
0-1
2+3(0)-5(0)(0)
2
(0, 0.5, 1) for final
answer.
- lim
3/2 (x-1/2-1)
x³/2 (2+3x-1/2-5x-³/2)
x +x
= lim
+-1
x→ 2+ 亦
√x
lim +-1
2+3.lim -5.lim 4- lim
0-1
2+3(0)-5(0)(0) 2
-1
(0, 0.5, 1) for extracting
Cancelling the common
factor
from the top
and the bottom
(0, 0.5, 1) for
intermediate algebra
and limit laws
(0, 0.5, 1) for final
answer.
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