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Question 1 (1 point) 8b. In three-space, find the intersection point of the two lines: (x, y, z) = (-2, 3, -3) + x = 3-t s(1, -1, 2) and y = −5+2t. (3,-5,7) (-2, 3, -3) 2=7-2t (0, 1, 1) (-1,2,-2) Question 2 (1 point) 2b. A line passes through the points M(0, 1, 4) and N(1, 4, 5). Find a vector equation of the line. (x, y, z) = (1, 3, 1) + t(0, 1, 4) (x, y, z) = (0, 1, 4) + t(1, 4, 5) (x, y, z) = (1, 4, 5) + t(1, 3, 1) (x, y, z) =(1, 3, 1) + t(1, 4, 5)

Question 1 (1 point) 8b. In three-space, find the intersection point of the two lines: (x, y, z) = (-2, 3, -3) + x = 3-t s(1, -1, 2) and y = −5+2t. (3,-5,7) (-2, 3, -3) 2=7-2t (0, 1, 1) (-1,2,-2) Question 2 (1 point) 2b. A line passes through the points M(0, 1, 4) and N(1, 4, 5). Find a vector equation of the line. (x, y, z) = (1, 3, 1) + t(0, 1, 4) (x, y, z) = (0, 1, 4) + t(1, 4, 5) (x, y, z) = (1, 4, 5) + t(1, 3, 1) (x, y, z) =(1, 3, 1) + t(1, 4, 5)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 1 (1 point) 8b. In three-space, find the intersection point of the two lines: (x, y, z) = (-2, 3, -3) + x = 3-t s(1, -1, 2) and y = −5+2t. (3,-5,7) (-2, 3, -3) 2=7-2t (0, 1, 1) (-1,2,-2) Question 2 (1 point) 2b. A line passes through the points M(0, 1, 4) and N(1, 4, 5). Find a vector equation of the line. (x, y, z) = (1, 3, 1) + t(0, 1, 4) (x, y, z) = (0, 1, 4) + t(1, 4, 5) (x, y, z) = (1, 4, 5) + t(1, 3, 1) (x, y, z) =(1, 3, 1) + t(1, 4, 5)
Transcribed Image Text:Question 1 (1 point) 8b. In three-space, find the intersection point of the two lines: (x, y, z) = (-2, 3, -3) + x = 3-t s(1, -1, 2) and y = −5+2t. (3,-5,7) (-2, 3, -3) 2=7-2t (0, 1, 1) (-1,2,-2) Question 2 (1 point) 2b. A line passes through the points M(0, 1, 4) and N(1, 4, 5). Find a vector equation of the line. (x, y, z) = (1, 3, 1) + t(0, 1, 4) (x, y, z) = (0, 1, 4) + t(1, 4, 5) (x, y, z) = (1, 4, 5) + t(1, 3, 1) (x, y, z) =(1, 3, 1) + t(1, 4, 5)
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