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(a) Expand 9 1 + x as a power series. 00 09-2x+9 ○ 9 - 00 n = 0 9 - 00 9 -x+ n = 2 00 + 1)! -x" 9(-1) (2n+ 4"-n! Σ (2n + 1)! 9- 4"-n! n = 2 9(-1)+: 9(-1)+11·5.9. 9 x + Σ9-1)01.5.9. n = 2 9 00 9 - 2x + n = 2 9(-1)" 4 7 (4n+1) 4" - n! . 4"-n! (4n - 3) 4.n! (3n - 2) хл (b) Use part (a) to estimate 9 1.1 correct to three decimal places.

(a) Expand 9 1 + x as a power series. 00 09-2x+9 ○ 9 - 00 n = 0 9 - 00 9 -x+ n = 2 00 + 1)! -x" 9(-1) (2n+ 4"-n! Σ (2n + 1)! 9- 4"-n! n = 2 9(-1)+: 9(-1)+11·5.9. 9 x + Σ9-1)01.5.9. n = 2 9 00 9 - 2x + n = 2 9(-1)" 4 7 (4n+1) 4" - n! . 4"-n! (4n - 3) 4.n! (3n - 2) хл (b) Use part (a) to estimate 9 1.1 correct to three decimal places.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(a) Expand 9 1 + x as a power series. 00 09-2x+9 ○ 9 - 00 n = 0 9 - 00 9 -x+ n = 2 00 + 1)! -x" 9(-1) (2n+ 4"-n! Σ (2n + 1)! 9- 4"-n! n = 2 9(-1)+: 9(-1)+11·5.9. 9 x + Σ9-1)01.5.9. n = 2 9 00 9 - 2x + n = 2 9(-1)" 4 7 (4n+1) 4" - n! . 4"-n! (4n - 3) 4.n! (3n - 2) хл (b) Use part (a) to estimate 9 1.1 correct to three decimal places.
Transcribed Image Text:(a) Expand 9 1 + x as a power series. 00 09-2x+9 ○ 9 - 00 n = 0 9 - 00 9 -x+ n = 2 00 + 1)! -x" 9(-1) (2n+ 4"-n! Σ (2n + 1)! 9- 4"-n! n = 2 9(-1)+: 9(-1)+11·5.9. 9 x + Σ9-1)01.5.9. n = 2 9 00 9 - 2x + n = 2 9(-1)" 4 7 (4n+1) 4" - n! . 4"-n! (4n - 3) 4.n! (3n - 2) хл (b) Use part (a) to estimate 9 1.1 correct to three decimal places.
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