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5-45 A sample of an unknown peptide was divided into two aliquots, acid. One aliquot was treated with trypsin; the other was treated with Given the following sequences of the resulting fragments (as determined by Edman degradation), deduce the se- quence of the original peptide. Trypsin treatment cyanogen bromide. Asn-Thr-Trp-Met-Ile-Lys Gly-Tyr-Met-Gln-Phe Val-Leu-Gly-Met-Ser-Arg Cyanogen bromide treatment Gln-Phe Val-Leu-Gly-Met Ile-Lys-Gly-Tyr-Met Ser-Arg-Asn-Thr-Trp-Met

5-45 A sample of an unknown peptide was divided into two aliquots, acid. One aliquot was treated with trypsin; the other was treated with Given the following sequences of the resulting fragments (as determined by Edman degradation), deduce the se- quence of the original peptide. Trypsin treatment cyanogen bromide. Asn-Thr-Trp-Met-Ile-Lys Gly-Tyr-Met-Gln-Phe Val-Leu-Gly-Met-Ser-Arg Cyanogen bromide treatment Gln-Phe Val-Leu-Gly-Met Ile-Lys-Gly-Tyr-Met Ser-Arg-Asn-Thr-Trp-Met

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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the exact stoichiometry is difficult because if alargle omant of PITC lyzed. added then both the first and the sere d amino acids will recict to it. So this will generate a dade sigral that would lead to confusion that terminalom ne geld which r trop amper was divided into two aliquots. acid. which of the 5-45 A sample of an unknown with One aliquot was treated with trypsin; the other was treated cyanogen bromide. Given the following sequences of the resulting fragments (as determined by Edman degradation), deduce the se- quence of the original peptide. Trypsin treatment Asn-Thr-Trp-Met-Ile-Lys Gly-Tyr-Met-Gln-Phe Val-Leu-Gly-Met-Ser-Arg Cyanogen bromide treatment Gln-Phe Val-Leu-Gly-Met Ile-Lys-Gly-Tyr-Met Ser-Arg-Asn-Thr-Trp-Met
Transcribed Image Text:the exact stoichiometry is difficult because if alargle omant of PITC lyzed. added then both the first and the sere d amino acids will recict to it. So this will generate a dade sigral that would lead to confusion that terminalom ne geld which r trop amper was divided into two aliquots. acid. which of the 5-45 A sample of an unknown with One aliquot was treated with trypsin; the other was treated cyanogen bromide. Given the following sequences of the resulting fragments (as determined by Edman degradation), deduce the se- quence of the original peptide. Trypsin treatment Asn-Thr-Trp-Met-Ile-Lys Gly-Tyr-Met-Gln-Phe Val-Leu-Gly-Met-Ser-Arg Cyanogen bromide treatment Gln-Phe Val-Leu-Gly-Met Ile-Lys-Gly-Tyr-Met Ser-Arg-Asn-Thr-Trp-Met
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