5 3 6 18 : 20 10: For the following reaction, use the plots below and the information on them to determine the half-life (in s) of this reaction: Reaction: N₂O5 (g) → N2 (g) + (5/2)O2(g) -> [N205] vs Time 0.025 0.020 y = -1.958E-05x + 1.874E-02 R2 = 0.9717 0.015 0.010 ........ 0.005 0.000 200 300 400 500 600 Time (s) In[N205] vs Time Equations. [N205] In[N205] 1/[N205] -3.5 -4.0 4.5 -5.0 -5.5 200 160 120 80 40 0 ****** 0 0 ******** 0 100 100 200 1/[N205] vs Time y = 1.606E-01x + 4.141E+01 R² = 0.9729 400 500 Time (s) y = -1.697E-03x - 3.913 R² = 0.9999 700 500 600 Time (s) 300 400 100 200 300 600 700 700 800 800 800
5 3 6 18 : 20 10: For the following reaction, use the plots below and the information on them to determine the half-life (in s) of this reaction: Reaction: N₂O5 (g) → N2 (g) + (5/2)O2(g) -> [N205] vs Time 0.025 0.020 y = -1.958E-05x + 1.874E-02 R2 = 0.9717 0.015 0.010 ........ 0.005 0.000 200 300 400 500 600 Time (s) In[N205] vs Time Equations. [N205] In[N205] 1/[N205] -3.5 -4.0 4.5 -5.0 -5.5 200 160 120 80 40 0 ****** 0 0 ******** 0 100 100 200 1/[N205] vs Time y = 1.606E-01x + 4.141E+01 R² = 0.9729 400 500 Time (s) y = -1.697E-03x - 3.913 R² = 0.9999 700 500 600 Time (s) 300 400 100 200 300 600 700 700 800 800 800
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
9
Please answer the question(attached image) by picking one of the following options
1)0.408s
2)129s
3)258s
4)408s
5)none of the above
![5
4
_6
18
:
20
10:
For the following reaction, use the plots below and the information on them to
determine the half-life (in s) of this reaction:
Reaction: N₂O5 (g) → N₂ (g) + (5/2)O2(g)
[N205] vs Time
0.025
0.020
y = -1.958E-05x + 1.874E-02
0.015
R² = 0.9717
0.010
0.005
0.000
300
400 500 600 700
Time (s)
y = -1.697E-03x - 3.913
R² = 0.9999
600
Equations.
[N205]
In [N205]
1/[N205]
-3.5
-4.0
4.5
-5.0
-5.5
200
160
120
80
40
0
0
100
100
200
300
400 500
Time (s)
1/[N205] vs Time
y = 1.606E-01x + 4.141E+01
R² = 0.9729
300
500
200
In [N205] vs Time
100
200
400
Time (s)
600
700
700
800
800
800](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F28ec4ff1-b4cd-497b-aede-a2aa47bbf04f%2F681ed79a-5206-4c9b-983f-7ba8b3f61c61%2F965gp9a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5
4
_6
18
:
20
10:
For the following reaction, use the plots below and the information on them to
determine the half-life (in s) of this reaction:
Reaction: N₂O5 (g) → N₂ (g) + (5/2)O2(g)
[N205] vs Time
0.025
0.020
y = -1.958E-05x + 1.874E-02
0.015
R² = 0.9717
0.010
0.005
0.000
300
400 500 600 700
Time (s)
y = -1.697E-03x - 3.913
R² = 0.9999
600
Equations.
[N205]
In [N205]
1/[N205]
-3.5
-4.0
4.5
-5.0
-5.5
200
160
120
80
40
0
0
100
100
200
300
400 500
Time (s)
1/[N205] vs Time
y = 1.606E-01x + 4.141E+01
R² = 0.9729
300
500
200
In [N205] vs Time
100
200
400
Time (s)
600
700
700
800
800
800
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