2. Determine the empirical formula of the oxide of nickel, showing your work cle 3. Name the compound according to IUPAC conventions. Eine

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**Question 2: Determining the Empirical Formula of Nickel Oxide**

2. Determine the empirical formula of the oxide of nickel, showing your work clearly.

- Begin by analyzing the mass percentages or ratios of nickel and oxygen.
- Convert these percentages to moles by dividing by the atomic masses.
- Simplify the mole ratios to the smallest whole numbers to find the empirical formula.

**Question 3: Naming Compounds Using IUPAC Conventions**

3. Name the compound according to IUPAC conventions.

- Follow the IUPAC naming conventions to accurately name the compound.
- Ensure the name reflects the composition and structure of the compound.
  
For example, if the empirical formula is \( \text{NiO} \), the IUPAC name would be Nickel(II) Oxide.
Transcribed Image Text:**Question 2: Determining the Empirical Formula of Nickel Oxide** 2. Determine the empirical formula of the oxide of nickel, showing your work clearly. - Begin by analyzing the mass percentages or ratios of nickel and oxygen. - Convert these percentages to moles by dividing by the atomic masses. - Simplify the mole ratios to the smallest whole numbers to find the empirical formula. **Question 3: Naming Compounds Using IUPAC Conventions** 3. Name the compound according to IUPAC conventions. - Follow the IUPAC naming conventions to accurately name the compound. - Ensure the name reflects the composition and structure of the compound. For example, if the empirical formula is \( \text{NiO} \), the IUPAC name would be Nickel(II) Oxide.
**Step 2**

**b)**

**d)** Mass percent of Ni = \(\frac{{\text{amount of Ni in g}}}{{\text{total amount of NiO in g (sample)}}} \times 100\)

= \(\left(\frac{{0.721 \, \text{g}}}{{1.012 \, \text{g}}}\right) \times 100 = 71.24\%\)

**e)** Mass percent of oxygen (O) = \(\frac{{\text{amount of O in g}}}{{\text{total amount of NiO in g (sample)}}} \times 100\)

= \(\left(\frac{{0.291 \, \text{g}}}{{1.012 \, \text{g}}}\right) \times 100 = 28.75\%\)
Transcribed Image Text:**Step 2** **b)** **d)** Mass percent of Ni = \(\frac{{\text{amount of Ni in g}}}{{\text{total amount of NiO in g (sample)}}} \times 100\) = \(\left(\frac{{0.721 \, \text{g}}}{{1.012 \, \text{g}}}\right) \times 100 = 71.24\%\) **e)** Mass percent of oxygen (O) = \(\frac{{\text{amount of O in g}}}{{\text{total amount of NiO in g (sample)}}} \times 100\) = \(\left(\frac{{0.291 \, \text{g}}}{{1.012 \, \text{g}}}\right) \times 100 = 28.75\%\)
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