4:28 1 l LTE Question 4 of 14 Submit Determine the number of grams of C4H10 that are required to completely react to produce 8.70 mol of CO2 according to the following combustion reaction: C4H10(g) + 13 O2(g) → CO2(g) + 10 H20(g) х STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) %3D 0.0374 4.35 g CO2 6.022 x 1023 58.14 44.01 mol CO2 2.18 18.02 g H20 10 13 8.70 mol H20 208.00 126 mol C4H10 Tap here or pull up for additional resources

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4:28 1
l LTE
Question 4 of 14
Submit
Determine the number of grams of C4H10 that are
required to completely react to produce 8.70
mol of CO2 according to the following combustion
reaction:
C4H10(g) +
13
O2(g) →
CO2(g) +
10
H20(g)
х
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
%3D
0.0374
4.35
g CO2
6.022 x 1023
58.14
44.01
mol CO2
2.18
18.02
g H20
10
13
8.70
mol H20
208.00
126
mol C4H10
Tap here or pull up for additional resources
Transcribed Image Text:4:28 1 l LTE Question 4 of 14 Submit Determine the number of grams of C4H10 that are required to completely react to produce 8.70 mol of CO2 according to the following combustion reaction: C4H10(g) + 13 O2(g) → CO2(g) + 10 H20(g) х STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) %3D 0.0374 4.35 g CO2 6.022 x 1023 58.14 44.01 mol CO2 2.18 18.02 g H20 10 13 8.70 mol H20 208.00 126 mol C4H10 Tap here or pull up for additional resources
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