OSTARTING AMOUNTescX#According to the balanced reaction below, calculate the moles of NH3 that form whenmol of N₂H4 completely reactsADD FACTORX()32.063.2mol NH3$4.21%3g N₂H4Question 24 OT 38ofN₂H4(1)→-6.022 x 10234.2mol N₂34 NH3(g) + N₂(g)65.6ANSWERg N₂28.02O716.817.04mol N₂H4RESET2g NH34Feb 23

Since, Moles is the ratio of mass to the molar mass of that atom or molecules. Thus,

Answered: According to the balanced reaction…

According to the balanced reaction below, calculate the moles of NH, that form when 4.2 mol of N₂H completely reacts 3 N₂H₂(1) 1 4 NH₂(g) + N₂(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

O
STARTING AMOUNT
esc
X
#
According to the balanced reaction below, calculate the moles of NH3 that form when
mol of N₂H4 completely reacts
ADD FACTOR
X
()
32.06
3.2
mol NH3
$
4.2
1
%
3
g N₂H4
Question 24 OT 38
of
N₂H4(1)→
-
6.022 x 1023
4.2
mol N₂
3
4 NH3(g) + N₂(g)
6
5.6
ANSWER
g N₂
28.02
O
7
16.8
17.04
mol N₂H4
RESET
2
g NH3
4
Feb 23

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